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omeli [17]
3 years ago
15

The moon clearly exhibits a light and dark portion during most of the month except during full moon. What causes the dark portio

n of any phase to change in size, that is, become either more or less black ?
Physics
1 answer:
mylen [45]3 years ago
8 0
While rotating around Earth the Moon also rotates around it's axis. These two rotations have almost same duration (27.3 and 27 days respectively). This is the reason why we always see the same side of Moon.

The dark part of a Moon is the part where there is night on the Moon, meaning there is no sunlight visible. This dark part depends on the Moon's position relative to Earth and Sun. The change in size is due to part of Moon-day. Dark part of Moon has night, bright part has day and the boundary has either sunrise or sunset.
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Carefully consider how the accelerations a1 and a2 are related. Solve for the magnitude of the acceleration, a1, of the block of
eduard

Answer:

a1 = 3.68m/s²

Explanation:

Given values:

Mass of the block placed on the table, m1 = 12.25 kg

Mass of the block hanging vertically, m2 = 7.5 kg

Acceleration due to gravity, g = 9.8 m/s2

Tension in the string is T

Let the acceleration of mass 1 and mass 2 be a1 and a2

a1 and a2 are equal in magnitude but different in direction. This because the string does not stretch. Hence the two bodies must move equal distances in equal times, and so their speechless at any instant must be equal. When the speeds change , they change by equal amounts in a given time, so the acceleration of the two bodies must have the same magnitude a,

a = m2*g/(m1 + m2)

a = 7.5 x 9.8 / (12.5 + 7.5)

a = 3.68 m/s²

a1 = a2 = 3.68m/s²

a1 is directed to the right and a2 is directed downwards

Below is a diamonds to show the geometrical arrangements of both masses

7 0
4 years ago
What is the focal length of concave mirror that magnifies , by a factor of +3.2 , an object that is placed 30cm from the mirror?
guapka [62]

Answer:

23 cm

Explanation:

The formula for magnification is;

Magnification = image distance / object distance

use values as;

3.2 = v / 30   where v is image distance

v =30*3.2

v=96 cm

The relationship of the focal length with image distance and object distance is expressed as;

\frac{1}{u} +\frac{1}{v} =\frac{1}{f}

where f is the focal length and u is object distance

use values in the equation as;

\frac{1}{30} +\frac{1}{96 }  =\frac{1}{f}

\frac{1}{f} =\frac{7}{160}

f=160/7

f=22.86

f= 23 cm ----------nearest a cm

7 0
3 years ago
The frequency of the harmonics following a fairly simple pattern, as described in the text. If the frequency of the fundamental
zalisa [80]

Answer:

f2 = 140 Hz

Explanation:

let fundamental frequency is f1 = 70.0 Hz

formula for finding the higher frequency when fundamental frequency is known

fn = n f1          (where f1 is fundamental frequency and n = 1,2,3,4,5...........)

for the second frequency n=2

f2 = 2 × 70.0 Hz

f2 = 140 Hz

6 0
4 years ago
A scientist counts the number of bacteria colonies growing in each of six lab dishes.
Nadusha1986 [10]

13 is the mode because it is the number that appears most often

:)

5 0
3 years ago
Read 2 more answers
Which statements accurately describe mechanical waves​
AleksAgata [21]

Answer:

Explanation:

so a mechanical wave transfers energy through a medium but unlike other waves that move through very long distances

the distance of the mechanical wave is different

7 0
3 years ago
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