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MatroZZZ [7]
3 years ago
7

Saturated steam at 125 kpa is compressed adiabatically in a centrifugal compressor to 700 kpa at the rate of 2.5 kg⋅s−1. the com

pressor efficiency is 78%. what is the power requirement of the compressor and what are the enthalpy and entropy of the steam in its final state
Physics
1 answer:
Tpy6a [65]3 years ago
5 0
M° = 2.5 kg/sec
For saturated steam tables
at p₁ = 125Kpa
hg = h₁ = 2685.2 KJ/kg
SQ = s₁ = 7.2847 KJ/kg-k
for isotopic compression
S₁ = S₂ = 7.2847 KJ/kg-k
at 700Kpa steam with S = 7.2847
h₂ 3051.3 KJ/kg
Compressor efficiency
h =  0.78
0.78 = h₂ - h₁/h₂-h₁
0.78 = h₂-h₁ → 0.78 = 3051.3 - 2685.2/h₂ - 2685.2
h₂ = 3154.6KJ/kg
at 700Kpa with 3154.6 KJ/kg
enthalpy gives
entropy S₂ = 7.4586 KJ/kg-k
Work = m(h₂ - h₁) = 2.5(3154.6 - 2685.2
W = 1173.5KW
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Represent 8953 ms with Sl units having an appropriate prefix Express your answer to four significant figures and include the app
tatyana61 [14]

Answer:

8.953 s

Explanation:

Here a time of 8953 ms is given.

Some of the prefixes of the SI units are

mili = 10⁻³

micro = 10⁻⁶

nano = 10⁻⁹

kilo = 10³

Mega = 10⁶

Each prefix increases or decreases by a factor of 10³

The number is 8953.0

Here, the only solution where the number of significant figures is mili.  If any other prefix is chosen then the significant figures will increase.

1 milisecond = 1000 second

1\ second=\frac{1}{1000}\ milisecond

\\\Rightarrow 8953\ milisecond=\frac{8953}{1000}\ second\\ =8.953\ second

So, 8953 ms = 8.953 s

8 0
3 years ago
A small toy cart equipped with a spring bumper rolls toward a wall with a speed of v . The cart rebounds from the wall, with the
anastassius [24]

Using the initial momentum vector as a basis, the change in momentum vector Δp for the cart is drawn as shown in the attachment.

<h3>Further explanation</h3>

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

\large {\boxed {F = ma }

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

\texttt{ }

<u>Given:</u>

Initial speed of cart = v_i = v

Final speed of cart = v_f = v

<u>Unknown:</u>

The change in momentum of cart = I  = ?

<u>Solution:</u>

I = \Delta p

I = p_f - p_i

I = mv_f - mv_i

I = m ( v_f - v_i )

I = m ( -v - v )

I = m ( -2v )

I = -2mv

I = -2p_i

\texttt{ }

<em>From the results above, we can conclude that the change in momentum vector Δp is twice the initial momentum vector p_i but in opposite direction.</em>

The vector <em>Δp could be drawn as shown </em><em>in the attachment.</em>

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441
  • Newton's Law of Motion: brainly.com/question/10431582
  • Example of Newton's Law: brainly.com/question/498822

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

#LearnWithBrainly

5 0
3 years ago
I don't understand how to find the frequency and period of wavelengths. Can anyone help me?
nordsb [41]

Frequency of a wave =

                 (speed of the wave) divided by (wavelength)
or
                 (1) divided by (period of the wave) .


Period of the wave =

                   (wavelength) divided by (speed of the wave)
or
                   (1) divided by (frequency of the wave) .
3 0
3 years ago
Please help me<br> asdfghjklqwertyuioikjhgfrfghjuhygfdfghjmhgtfhjk
sertanlavr [38]

Answer:

c

Explanation:

the moon moves around earth

5 0
2 years ago
What does the SLOPE of a Velocity-Time graph represent? *<br> 1 point
lyudmila [28]

Acceleration

Explanation:

  • In the Velocity-Time graph Velocity is taken in Y-Axis and plotted against Time in X-Axis.
  • The unit of velocity is mentioned in m/s and unit of time is mentioned in seconds.
  • Here we can analyze the instantaneous acceleration and displacement covered.
  • From the slope we can get the body accelerated.
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  • We can calculate both average and Instantaneous acceleration from the slope of this graph.

6 0
3 years ago
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