Question

What mass of NH3 can be made from 35.0g of N2?

Answer 1

Answer:

$Mass_{NH_3}= 42.5775\ g$

Explanation:

Moles of $N_2$:-

Mass = 35.00 g

Molar mass of $N_2$ = 28.014 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{35.00\ g}{28.014\ g/mol}$

$Moles_{N_2}= 1.25\ mol$

According to the reaction:-

$N_2_{(g)} + 3H_2_{(g)}\rightarrow 2NH_3_{(g)}$

1 mole of $N_2$ on reaction forms 2 moles of $NH_3$

1.25 mole of $N_2$ on reaction forms 2*1.25 moles of $NH_3$

Moles of $NH_3$  = 2.5 moles

Molar mass of $NH_3$ = 17.031 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$2.5\ mol= \frac{Mass}{17.031\ g/mol}$

$Mass_{NH_3}= 42.5775\ g$

Answer 2

Formation of ammonia by nitrogen and hydrogen is habers process wher 28g N2 results in formation of 34g NH3
so 35g N2 will form 34*35/28=42.5g NH3 where it given that reaction takes place in excess of H2
N2+3H2 gives 2NH3