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4 years ago

Is the indicator generally added to the titrant or the analyte in a titration?

2 answers:

5 0

In a titration process, the unknown or the analyte with a known volume is placed in a flask and the titrant whose concentration is known is placed in the burette. The indicator in the titration process is generally added to the flask with the analyte.

dsp734 years ago

5 0

Answer:

The correct answer is "the analyte".

Explanation:

Titration is a method of quantitative chemical analysis used to determine the unknown concentration of a reagent from a reagent with a known concentration.

A reagent called a "titrator" of known volume and concentration is used to react with an analyte solution of unknown concentration. The endpoint is the point at which the titration ends, and is determined by the use of an indicator, which is added to the analyte.

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Calculate the number of moles found in 88.02g of CO2

bija089 [108]

Answer:

2.00moles

Explanation:

mol=mass/mr

88.02/ [12+2(16)] = 2.00

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3 years ago

How many protons are in nitrogen

Hatshy [7]

Answer:

Explanation:

There are 7 protons in nitrogen

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3 years ago

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A sample of an unknown gas takes 222 s to diffuse through a porous plug at a given temperature. At the same temperature, N2(g) t

gulaghasi [49]

Answer:

$\large \boxed{\text{45.1 g/mol}}$

Explanation:

Graham’s Law applies to the diffusion of gases:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r \propto \dfrac{1}{\sqrt{M}}$

If you have two gases, the ratio of their rates of diffusion is

$\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}$

The time for diffusion is inversely proportional to the rate.

$\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}$

Data:

t₂ = 222 s

t₁ = 175 s

M₁ = 28.01

Calculation :

$\begin{array}{rcl}\dfrac{222}{175} & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.269 & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.609 & = & \dfrac{M_{2}}{28.01}\\\\M_{2} & = & 1.609 \times 28.01\\ & = & \textbf{45.1 g/mol}\\\end{array}\\\text{The molar mass of the unknown gas is $\large \boxed{\textbf{45.1 g/mol}}$}$

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3 years ago

How many formula units are there in 103 g of NaCl?

charle [14.2K]

Answer:

1.059 x 10^24 formula units

Explanation:

103/58.44 = 1.76 moles NaCl

1.76 x 6.022 x 10^23 = 1.059 x 10^24

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3 years ago

Please can I have help on question e as I’m really stuck.I promise I’ll give out brainiest

Natasha_Volkova [10]

The relative atomic mass of element A : 6.075 u

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

Atomic mass is the average atomic mass of all its isotopes

Mass atom X = mass isotope 1 . % + mass isotope 2.% ...

Element A

mass number of isotope 1 = 6 , percent : 92.5%

mass number of isotope 2 = 7, percent : 7.5

Relative atomic mass of element A

$\tt = 92.5\%\times 6+7.5\%\times 7\\\\=5.55+0.525=6.075~u$

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3 years ago