Solution
write the division as a fraction = 12y^4-4y^3 - 6y^2 + 36y - 22 over y-3 multiplied by r over y-3
r ×(2y^4 - 4y^3- 16y^2 + 36y- 22) over (y-3)^2
2ry^4 - 4ry^3 - 16ry^2 + 36ry - 22r over (y-3)^2
First step, divide 6 from both sides.
t/6=r^2+1
second step, subtract 1 from both sides
t/6 -1=r^2
Now take the square root of each side.

Done!
Answer:
it goes 0 then 1/4 in the first notch 1/2 in the second notch 3/4 in the third notch then the number 1 on the fourth
Step-by-step explanation:
Hope that helps.
Answer:
-45
Step-by-step explanation: no explanation