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Mekhanik [1.2K]
3 years ago
11

ben is filling up his cylinder shaped pool up to 80% of its capacity . If his is 6 feet deep and has a diameter of 18 feet, how

much water will he put in the pool.
Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

You will put 1220.83ft³ of water in the pool

Step-by-step explanation:

radius = half of diameter

d = 18ft

r = 18ft / 2 = 9ft

To calculate the volume of a cylinder we have to use the following formula:

v = volume

h = height = 6ft

π = 3.14

r = radius = 9ft

v = (π * r²) * h

we replace with the known values

v = (3.14 * (9ft)²) * 6ft

v = (3.14 * 81ft²) * 6ft

v = 254.34ft² * 6ft

v = 1526.04ft³

The volume of the cylinder is 1526.04ft³

If it is filled to 80% then we have to multiply the volume by 80/100

1526.04ft³  * 80/100 = 1220.83ft³

You will put 1220.83ft³ of water in the pool

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Step-by-step explanation:

The question you are asking is a circle with shaded portion and a portion not shaded  . The radius of the circle is given as 13 yards . H is the center of the circle and unshaded part of the the sector has an angle of 126°.

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