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Montano1993 [528]
3 years ago
14

Ms. Ghandi runs 1 mile each morning and 1 mile each evening. She also does 10 pushups each morning and evening.

Mathematics
1 answer:
Verdich [7]3 years ago
3 0
Since there are 7 days in 1 week and 2 times excercise in 1 day, she will exercise 7(2(m+10p)) = 7(2m+20p) = 14m+140p
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URGENT, PLEASE ANSWER.
nata0808 [166]

Answer: x= -1

Step-by-step explanation:

1 Subtract 44 from both sides.

x=3-4x=3−4

2 Simplify  3-43−4  to  -1−1.

x=-1x=−1

5 0
2 years ago
Read 2 more answers
I need to know what to do for this problem. I am confused. Thanks♡
steposvetlana [31]
$1,154 will be what each kid needs to raise, you must add up both travel expenses, which totals $10,386, and divide that with the number of children (9), and you get your answer:)! hope this helps.
6 0
3 years ago
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In an arithmetic series, what is the sum of the first 22 terms if the first term is 12 and the common difference is 3?
Vilka [71]

Answer:

561

Step-by-step explanation:

an = dn - (a-d)

The difference is 3.

The first term is 12.

an = 3n - (12-3)

an = 3n - 9

Put n as 1, 2, 3, 4, 5 ....22.

3(1) - 9 = -6

3(2) - 9 = -3

3(3) - 9 = 0

3(4) - 9 = 3

3(5) - 9 = 6

...

3(22) - 9 = 57

Add the first 22 terms.

-6+-3+0+3+6+9+12+15+18+21+24+27+30+33+36+39+42+45+48+51+54+57

= 561

4 0
2 years ago
A book designer decided that the pages of a book should have 1-in. margins at the top and bottom and 1 2 in. margins on the side
alexgriva [62]

Answer:

A = 54.8 - (1200/x) - 2x

Step-by-step explanation:

Given <em>x</em> the wide and <em>y</em> the height, we have

x*y = 50

⇒  y = 50/x

The area of the printed region is A = w*h

where

Wide: w = (x-2*1.2) = x-2.4

Height: h= (y-2*1) = y-2

then

A = (x-2.4)(y-2) = xy - 2.4y - 2x + 4.8 = 50 - 24*(50/x) - 2x + 4.8

⇒  A = 54.8 - (1200/x) - 2x

5 0
3 years ago
F the radius of a flying disc is 7.6 centimeters, what is the approximate area of the disc?
hoa [83]

Answer:

3.14x7.6=23.864 because raidus is the disctance around  one circle

Step-by-step explanation:

8 0
2 years ago
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