equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)
Perpendicular bisector lies at the midpoint of a line
Lets find mid point of (-9,-8) and (7,-4)
midpoint formula is


midpoint is (-1, -6)
Now find the slope of the given line
(-9,-8) and (7,-4)


Slope of perpendicular line is negative reciprocal of slope of given line
So slope of perpendicular line is -4
slope = -4 and midpoint is (-1,-6)
y - y1 = m(x-x1)
y - (-6) = -4(x-(-1))
y + 6 = -4(x+1)
y + 6 = -4x -4
Subtract 6 on both sides
y = -4x -4-6
y= -4x -10
equation for the perpendicular Bisector y = -4x - 10
The number (x) that is (=) 10 less than (-) 6
x = 6 - 10 Subtract
x = -4
Combine like terms
-6x^2+2y + -1 +2x^2 + -5y +3
( -6x^2+2x^2)+(2y-5y)+(-1+3)
= -4x^2+3y+2
Answer : C
I hope that's help !
Answer:
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<em>b) The coordinates of P are</em>
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Step-by-step explanation:
<u>Translation</u>
The dashed line shows the graph of the function

This function has a maximum value of 1, a minimum value of -1, and a center value of 0.
a)
Graph G shows the same function but translated by 2 units up, thus the equation of G is:

b) The coordinates of P correspond to the value of

The value of G is

Since


The coordinates of P are
