Two 0.50 gg spheres are charged equally and placed 2.5 cmcm apart. When released, they begin to accelerate at 170 m/s2m/s2 . Wha
1 answer:
Answer:
q = 76.8*10⁻⁹ C = 76.8 nC
Explanation:
Assuming no other forces acting on the charges, and that both spheres must be considered as point charges (and as point masses as well) , the force that is responsible for the initial acceleration is the electrostatic force, which obeys Coulomb´s Law.
According to Newton´s 2nd Law, this force is related with the mass and the acceleration as follows:
This same force, expressed as the electrostatic force, is as follows:
As both expressions for F are equal each other, we can solve for q:
⇒ q = 76.8*10⁻⁹ C = 76.8 nC
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Answer:
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2. D. 10 m/s
First of all, we need to calculate the total time the stone took to hit the ground. Since the vertical distance covered is S = 78.4 m, and since the motion is an accelerated motion with constant acceleration g=9.8 m/s^2, we have
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3. B=32.32 m
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And since the stone is traveling horizontally at v = 16 m/s, the horizontal distance covered is
So, the closest answer is B.