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3 years ago

What is stoichiometry used for?

Chemistry

1 answer:

Helga [31]3 years ago

5 0

The answer is B :) hope this helped at least

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Consider the following precipitation reaction: 2Na3PO4(aq)+3CuCl2(aq)→ Cu3(PO4)2(s)+6NaCl(aq)

Troyanec [42]

Answer:

V= 37.0 mL

Explanation:

First find the moles of the known substance (CuCl2)

n= cv

where

n is moles

c is concentration

v is volume ( in litres)

n= 0.108 × 0.0946

n=0.0102168

Using the mole ratio in the balanced reaction, we can find the moles of Na3PO4

n (Na3PO4)= n (CuCl2) × 2/3

=0.0102168 × 2/3

=0.0068112

Now we have all the necessary values to calculate the volume

v=n/c

v= 0.0068112/0.184

v= 0.0370173913 L

v= 37.0 mL

6 0

4 years ago

I need help. ASAP! Look at the picture below. (2)

ozzi

C. MgCl2

This structure forms a ionic bond, which are generally stronger than covalent bonds. All of the other choices are covalent.

5 0

4 years ago

How many molecules are in 4.92 moles of water?

bezimeni [28]

Answer:

Number molecules present = 4.92 multipled by avogadro's number.

4 0

3 years ago

If 16g of <img src="https://tex.z-dn.net/?f=CH_%7B4%7D" id="TexFormula1" title="CH_{4}" alt="CH_{4}" align="absmiddle" class="la

sammy [17]

43.56 grams of are produced if 16g of CH4 reacts with 64g of O2.

Explanation:

Balance equation for the reaction:

CH4 + 2O2⇒ CO2 +2H2O

Data given : mass of CH4 =16 grams atomic mass = 16.04 grams/mole

mass of water 36 gram atomic mass = 18 grams/moles

mass of CO2=? atomic mass = 44.01 grams/mole

number of moles = $\frac{mass}{atomic mass of one mole}$ equation 1

number of moles in CH4

n = $\frac{16}{16.04}$

= 0.99 moles

Since combustion is done in presence of oxygen hence it is an excess reagent and methane is limiting reagent so production of CO2 depends on it.

From the equation

1 mole of CH4 gave 1 mole of CO2

O.99 moles of CH4 will give x moles of CO2

$\frac{1}{1}$ = $\frac{x}{0.99}$

x = 0.99 moles of carbon dioxide

grams of CO2 = number of moles x atomic mass

= 0.99 x 44.01

= 43.56 grams of CO2 is produced.

4 0

3 years ago

You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1

jeka57 [31]

Answer:

$\boxed{\text{36 mL}}$

Explanation:

1. Write the balanced chemical equation.

$\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O$

2. Calculate the moles of HCOOH

$\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}$

3. Calculate the moles of NaOH.

$\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}$

4. Calculate the volume of NaOH

$c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}$

3 0

3 years ago