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gogolik [260]
4 years ago
9

You have 535 g of Zinc Chloride, ZnCl2. How many moles is this?

Chemistry
2 answers:
podryga [215]4 years ago
8 0

Answer:3.93moles

Explanation:

I mole of ZnCl2= 65+2(35.5)=136

If 136g of Zinc chloride,,=136grams

Then 535g is 535*1/136=3.93 moles of zinc chloride.

Noted that one mole of a substance contains its molar mass.

makkiz [27]4 years ago
5 0

Best Answer:  1 mole of zinc has a mass of 65.4 grams  

Therefore, if 1 mole is 65.4 grams, how many moles is 0.535g?  

1 mol = 65.4g  

? mol = 0.535g  

0.535g  

---------  

65.4g/mol  

(0.535g divided by 65.4grams per mole of Zinc)


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Which material is the least likely to be recognized as a mixture by looking at it under a microscope?
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I don't know what the options were but a material that is very likely going to be challenging to recognize under a microscope as a mixture is a homogeneous mixture. A homogenous mixture is uniform and thus hard to recognize as a mixture. An example is water!
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How many molecules of carbon dioxide, CO2, are present in 388.1 grams?
swat32

Answer:

53.11× 10²³ molecules

Explanation:

Given data:

Number of molecules of CO₂ = ?

Mass of CO₂ = 388.1 g

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of CO₂ = 12× 1 + 16×2

Molar mass of CO₂ = 44 g/mol

Now we will put the values in formula.

Number of moles = 388.1 g/ 44 g/mol

Number of moles = 8.82 moles

Now we will calculate the number of molecules by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

8.82 mol × 6.022 × 10²³ molecules / 1 mol

53.11× 10²³ molecules

6 0
3 years ago
Which moon phase does a solar eclipse occur in?
VARVARA [1.3K]

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Propane gas, C3H8, is sometimes used as a fuel. In order to measure its energy output as a fuel a 1.860 g sample was combined wi
lisov135 [29]

Answer:

The heat of the reaction is 105.308 kJ/mol.

Explanation:

Let the heat released during reaction be q.

Heat gained by water: Q

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Heat capacity of water ,c= 4.184 J/g°C

Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C

Q=mcΔT

Heat gained by bomb calorimeter =Q'

Heat capacity of bomb calorimeter ,C= 4.643 J/g°C

Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C

Q'=CΔT'=CΔT

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

q= -(Q+Q')

q = -mcΔT - CΔT=-ΔT(mc+C)

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0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.

The heat of the reaction will be:

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