The moles of the gas in the sample is 0.391 moles
calculation
by use of ideal gas equation, that is Pv=nRT
where n is number of moles
P(pressure)= 660 mmhg
R(gas constant) = 62.364 l.mmhg/mol.K
T(temperature)= 25 +273 = 298 k
by making n the subject of the formula
n= Pv/ RT
n is therefore= (660mm hg x11 L)/( 62.364 L.mmhg/mol.k x298 K) = 0.391 moles
Answer:
<h2>
2Al +
3CuO ==>
3Cu + Al2O3</h2>
Explanation:
So let's break this chemical equation down into 2 parts - Reactants and Products
Reactants = Al + CuO
Products = Cu + Al2O3
So the Chemical Reaction will be
Al + CuO ==> Cu + Al2O3
So the balanced equation will be,
2Al + 3CuO ==> 3Cu + Al2O3
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Answer:
M = 0.050 M
Explanation:
WE have an acid base reaction between NaOH and HCl. The reaction is as follow:
HCl + NaOH -------> NaCl + H₂O
As we can see, we have a balanced equation already, and we can also see that the mole ratio between the HCl and NaOH is 1:1, therefore we can use the following expression:
M₁V₁ = M₂V₂ 1: acid; 2: base
This expression is used when the reactions has reached the equivalence point. As we want to know the concentration of the base, we just solve for M₂ above so:
M₂ = M₁V₁ / V₂
All we have to do now is replace the given values and solve for the concentration:
M₂ = 0.15 * 27 / 81
<h2>
M₂ = 0.050 M</h2><h2>
This is the concentration of the base</h2>
A homogeneous mixture has the same uniform appearance and composition throughout. Many homogeneous mixtures are commonly referred to as solutions. A heterogeneous mixture consists of visibly different substances.
Answer:
VH2SO4 = 145.3 mL
Explanation:
Mw BaO2 = 169.33 g/mol
⇒ mol BaO2 = 53.5g * ( mol BaO2 / 169.33 g BaO2) = 0.545 mol BaO2
⇒according to the reaction:
mol BaO2 = mol H2SO4 = 0.545 mol
⇒ V H2SO4 = 0.545 mol H2SO4 * ( L H2SO4 / 3.75 mol H2SO4 )
⇒V H2SO4 = 0.1453 L (145.3 mL)
