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2 years ago

6

A thermometer reads an outside air temperature of 35 °C. What is the temperature in degrees Fahrenheit?

2 answers:

rjkz [21]2 years ago

8 0

35 degree Celsius × 9/5 + 32 = 95 Fahrenheit

Rasek [7]2 years ago

3 0

To convert take 1.8 * degrees C + 32
1.8 * 35 + 32
63 + 32 = 95 so C

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How do atoms in molecules bond? <br> plz answer I will give brainliest

spin [16.1K]

Answer:

Via covalent bonds

Explanation:

Atoms in molecules are bonded together via covalent bonds. Covalent bonds are bonds that are formed by sharing of the valence electrons between two atoms.

The atoms can be of the same kind or of different kinds.

In most molecules, the two atoms are connected by sharing of their valence electrons.
This way, each atom can attain stability by becoming isoelectric with the nearest noble gas.
Some molecules are monoatomic, some are polyatomic.

5 0

2 years ago

A mixture of XO2 (P = 3.00 atm) and O2 (P = 1.00 atm) is placed in a container. This elementary reaction takes place at 27 °C: 2

sukhopar [10]

Answer:

a) $\triangle G^{0} = 7.31 kJ/mol$

b) $K_{-1} = 0.0594 m^{-1} s^{-1}$

Explanation:

Equation of reaction:

$2 XO_{2} (g) + O_{2} (g) \rightleftharpoons 2XO_{3} (g)$

Initial pressure 3 1 0

Pressure change 2P 1P 2P

Total pressure = (3-2P) + (1-P) + (2P)

Total Pressure = 3.75 atm

(3-2P) + (1-P) + (2P) = 3.75

4 - P = 3.75

P = 4 - 3.75

P = 0.25 atm

Let us calculate the pressure of each of the components of the reaction:

Pressure of XO2 = 3 - 2P = 3 - 2(0.25)

Pressure of XO2 =2.5 atm

Pressure of O2 = 1 - P = 1 -0.25

Pressure of O2 = 0.75 atm

Pressure of XO3 = 2P = 2 * 0.25

Pressure of XO3 = 0.5 atm

From the reaction, equilibrium constant can be calculated using the formula:

$K_{p} = \frac{[PXO_{3}] ^{2} }{[PXO_{2}] ^{2}[PO_{2}] }$

$K_{p} = \frac{0.5^2}{2.5^2 *0.75} \\K_{p} = 0.0533 = K_{eq}$

Standard free energy:

$\triangle G^{0} = - RT ln k_{eq} \\\triangle G^{0} = -(0.008314*300* ln0.0533)\\\triangle G^{0} = 7.31 kJ/mol$

b) value of k−1 at 27 °C, i.e. 300K

$K_{1} = 7.8 * 10^{-2} m^{-2} s^{-1}$

$K_{c} = K_{p}RT\\K_{c} = 0.0533* 0.0821 * 300\\K_{c} = 1.313 m^{-1}$

$K_{-1} = \frac{K_{1} }{K_{c} } \\K_{-1} = \frac{7.8 * 10^{-2} }{1.313 }\\K_{-1} = 0.0594 m^{-1} s^{-1}$

6 0

2 years ago

Assuming a total pressure of 9.3 atmatm , what is the partial pressure of helium in the mixture of 98%% helium and 2.0%% oxygen

Paladinen [302]

Answer:

D0wnload Phot0Math......................

Explanation:

7 0

2 years ago

A 10 gram iron nail absorbed 125J of heat. What was the final temperature of the nail if the original temperature was 25°C?

valentina_108 [34]

Answer:

52.1 degrees C

Explanation:

We need to use the equation: q = mCΔT, where m is the mass in grams, C is the specific heat capacity, and ΔT is the change in temperature.

Here, m = 10 g and q = 125 J. The heat capacity of iron is about 0.461 J/(g * C). And, our initial temperature is 25. So:

125 J = (10 g) * (0.461 J/(g * C)) * (T_f - 25)

Solving for T_f (final temp), we get: 52.1 degrees C

Hope this helps!

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2 years ago

It refers to a charged particle or atom.

Kay [80]

<h2><u>QUE</u><u>STION</u></h2>

It refers to a charged particle or atom.

<h2><u>CHOI</u><u>CES</u></h2>

<u>A.</u><u> </u><u>molecule</u>

B. bromine

C. potassium

D. sulfur

<h2><u>ANSWER</u></h2>

<h3><u>C</u><u>.</u><u> </u><u>pottasium</u></h3>

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2 years ago