Each degree of 60 equal parts are called minutes
Answer:
The missing species is carbon-12
.
The nuclear equation should be
.
Explanation:
Let
represent the mass number of the missing species, and let
represent its atomic number.
.
For this question, there are three things to consider:
- The sum of the mass numbers should be conserved.
- Since there's no beta particle (
or
) involved, the sum of the atomic numbers should also be conserved. - The atomic number of the missing species should correspond to atomic symbol.
<h3>Mass Number</h3>
The sum of the mass numbers on the left-hand side of this reaction is:
.
The sum of the mass number on the right-hand side (including that of the missing species) is
.
These two numbers should be the same. In other words,
. Therefore, the mass number of the missing species would be
.
<h3>Atomic Number</h3>
The sum of the atomic numbers on the left-hand side of this reaction is:
.
The sum of the mass number on the right-hand side (including that of the missing species) is
.
These two numbers should be the same. In other words,
. Therefore, the mass number of the missing species would be
.
<h3>Symbol</h3>
The atomic number
of the missing species is
. Look up a modern periodic table. The element with atomic number
Answer:
I believe the answer is A and D.
I am unsure of C.
Fossil fuels . . . coal, oil, natural gas
Among primitive cultures, wood is an important source.
m = mass of the circular hoop
r = radius of the hoop
I = moment of inertia of the hoop
moment of inertia of the hoop about the center of hoop is given as
I = m r²
k = distance of the point of suspension from center of mass = r
using parallel axis theorem
I' = moment of inertia of hoop about the point of suspension
I' = I + m k²
I' = m r² + m k²
I' = m r² + m r²
I' = 2 m r²
Time period of oscillation for the hoop is given as
T = 2π sqrt(I'/mgk)
T = 2π sqrt(2 m r²/(mgr))
T = 2π sqrt(2 r/g)
since 2r = diameter = d
T = 2π sqrt(d/g)