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Troyanec [42]
3 years ago
13

What is fiery about igneous rocks?

Physics
2 answers:
xz_007 [3.2K]3 years ago
8 0
It is fiery because it is cooled molten magma
Sveta_85 [38]3 years ago
6 0
Igneous rocks are fiery because they are molten rocks that had solidified 
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Give two examples of contact force and non contact force
Crank

Answer:

Explanation:

The two examples of contact forces are frictional force and applied force. The two examples of noncontact forces are gravitational force and magnetic force.

5 0
2 years ago
Air enters a turbine operating at steady state at 8 bar, 1400 K and expands to 0.8 bar. The turbine is well insulated, and kinet
vladimir2022 [97]

To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables

Mathematically this can be determined as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

Where

T_1 =Temperature at inlet of turbine

T_2 = Temperature at exit of turbine

P_1 = Pressure at exit of turbine

P_2 =Pressure at exit of turbine

The steady flow Energy equation for an open system is given as follows:

m_i = m_0 = m

m(h_i+\frac{V_i^2}{2}+gZ_i)+Q = m(h_0+\frac{V_0^2}{2}+gZ_0)+W

Where,

m = mass

m_i = mass at inlet

m_0= Mass at outlet

h_i = Enthalpy at inlet

h_0 = Enthalpy at outlet

W = Work done

Q = Heat transferred

V_i = Velocity at inlet

V_0= Velocity at outlet

Z_i= Height at inlet

Z_0= Height at outlet

For the insulated system with neglecting kinetic and potential energy effects

h_i = h_0 + W

W = h_i -h_0

Using the relation T-P we can find the final temperature:

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

\frac{T_2}{1400K} = (\frac{0.8bar}{8nar})^{(\frac{1.4-1}{1.4})}

T_2 = 725.126K

From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK

So:

W = h_i -h_0

W = C_p (T_1-T_2)

W = 1.005(1400-725.126)

W = 678.248kJ/Kg

Therefore the maximum theoretical work that could be developed by the turbine is 678.248kJ/kg

5 0
4 years ago
Un bloque de 750 kg es empujado hacia arriba por una pista inclinada 15º respecto de la horizontal. El coeficiente de rozamiento
kotegsom [21]

Answer:

4776.98 N is the minimum force to start the rise.  

Explanation:

We can use the first Newton's law to find the minimum force to move the block.

So we will have:

F-W_{x}-F_{f}=0

Where:

  • F is the force
  • W(x) is the weight of the block in the x direction, W = mg*sin(15)
  • F(f) is the static friction force (F(f) = μN), μ is the static friction coefficient 0.4.

F=W_{x}+F_{f}=mgsin(15)+\mu N

F=mgsin(15)+\mu mgcos(15)

F=mg(sin(15)+\mu cos(15))

F=750*9.81(sin(15)+0.4*cos(15))

F=4776.98 N

Therefore 4776.98 N is the minimum force to move the block.

I hope it helps you!

8 0
3 years ago
Which is the formula for the functional group in an anime?
pshichka [43]

The formula for the functional group is NH2

8 0
3 years ago
How does a pedometer help people reach their fitness goals
goldfiish [28.3K]

how does a pedometer help people reach their fitness goals?

a. It measures calories burned.  

b. It usually doubles as an MP3 player and keeps people motivated.  

c. They count steps during a workout.  

d. They measure the number of lifts done per exercise.

8 0
3 years ago
Read 2 more answers
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