ANY closed orbit exists because of the centripetal force of gravity.
Without the force of gravity, the satellite would simply sail away
in a straight line.
The orbit you're describing happens to be a circular orbit, but it
doesn't have to be circular.
Answer:
The answer to your question is given below
Explanation:
Since both object A and B were dropped from the same height and the air resistance is negligible, both object A and B will get to the ground at the same time.
From the question, we were told that object A falls through a distance to dA at time t and object B falls through a distance of dB at time 2t.
Remember, both objects must get to the ground at the same time..!
Let the time taken for both objects to get to the ground be t.
Time A = Time B = t
But B falls through time 2t
Therefore,
Time A = Time B = 2t
Height = 1/2gt^2
For A:
Time = 2t
dA = 1/2 x g x (2t)^2
dA = 1/2g x 4t^2
For B
Time = t
dB = 1/2 x g x t^2
Equating dA and dB
dA = dB
1/2g x 4t^2 = 1/2 x g x t^2
Cancel out 1/2, g and t^2
4 = 1
4dA = dB
Divide both side by 4
dA = 1/4 dB
No it not because
Jill didn’t have actually have the gun
The problem should only have one part to it, but this one has two.
Before I can do the mass/energy conversion, I have to go and
look up the proton mass for myself ... go out and collect the straw
to make my bricks, as it were. As if the fabulous bounty of 7 points
makes it worth it. They make us do everything around here.
OK. In my Physics book⁽¹⁾, the proton rest mass is
1.67 x 10⁻²⁷ kg.
The formula that relates mass to the equivalent energy is
E = m c² .
The method of applying the formula is known as "plug in what you know",
as follows:
E = (mass) x (speed of light)²
= (1.67 x 10⁻²⁷ kg) x (3 x 10⁸ m/s)²
= (1.67 X 10⁻²⁷ Kg) x (9 x 10¹⁶ m²/s²)
= (1.5 x 10⁻¹⁰) (kg-m²/s²)
= 1.5 x 10⁻¹⁰ joule .
____________________________________
⁽¹⁾ Halliday, David and Resnick, Robert, Physics , John Wiley & Sons,
Inc., 1960, inside front cover, "SELECTED PHYSICAL CONSTANTS".
