Answer:
a = -4/5 m/s^2
Explanation:
Acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
a = (20 m/s - 60 m/s) / 50 s
a = -40 m/s / 50 s
a = -4/5 m/s^2
hope this helps! <3
The red laser will have a hotter temperature than the blue, so it is red because it is hot
<span>hope this helps!!!</span>
50 +50 =100 Since it’s sitting on a 50m cliff that’s high with a mass of 50 kg it would be adding because once it goes down it’s adding speed
I think trace 1 is ac and trace 2 if dc but i’m not sure what will happen when a higher frequency is added?
First we need to convert the mm to inches to make our computation
easier.
1mm = 0.0393701
32mm * 0.0393701 = 1.25 in
Solution:
C = 1/2d = ½ (1.25) = 0.625 in^4
Tension: tension = Te/J = 2T/ piC^3
= (2)(2500)/pi (0.0625)^3 = 6.519 x 10^3 psi = 6.519 ksi
Bending:
I = pi/4 * c^4 = 119.842 x 10^-3 in^4
M = (5)(600) = 3600 lb in
G = My/I = (3600)(0.625)/119.842 x 10^-3 = -18.775 x 10^2
psi = -18.775ksi
Gx = -18.775 ksi
Gy = 0
Txy = 6.519 ksi
G ave – ½ (Gx + Gy) = -9.387 ksi
R = sqrt (Gx – Gy/2)^2 + Txy^2 = sqrt(-9.387)^2 + (6.519)^2 = 11.429 ksi
1.
G1 = Gave + R = -9/387 + 11.429 = 2.04 ksi
G2 = Gave - R = -9/387 - 11.429 = -20.8
Tan 2ϴp = 2txy/Gx – Gy = 2(6.519)/-9.387 =
-1.3889
ϴp = -27.1 degrees and 62.9 degrees
2.
Tmax = R = 11.43 ksi
R = sqrt (Gx – Gy/2)^2 + Txy^2 = sqrt(-9.387)^2
+ (6.519)^2 = 11.429 ksi
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