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3 years ago

(1) Calculate the buoyant force on a 2.00-L helium balloon.

Physics

1 answer:

Mama L [17]3 years ago

6 0

Answer:

(1) 0.024 N

(2) 0.0093 N

Explanation:

When a body is immersed in a fluid partly of wholly it experience an upward force called buoyant force.

This buoyant force depends on the volume of the body, density of fluid and gravity.

(1) Volume = 2 L = 0.002 m^3

density of air, d = 1.23 kg/m^3

g = 9.8 m/s^2

The buoyant force is

F = V d g

F = 0.002 x 1.23 x 9.8 = 0.024 N

(2) mass, m = 1.5 g

The net vertical force is

F = F - m g

F = 0.024 - 0.0015 x 9.8 = 0.0093 N

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From the gravitational law, calculate the weight W (gravitational force with respect to the earth) of a 70 kg spacecraft traveli

Firlakuza [10]

Answer:

The value in Newton is $W = 631.92 \ N$

The value in pounds is $W = 142 \ lb$

Explanation:

From the question we are told that

The mass of the spacecraft is $m = 70 \ kg$

The distance above the earth is $d = 275 \ km = 275000 \ m$

Generally the gravitational force with respect to the earth is mathematically represented as

$W = \frac{G * m * m_e}{ (d + r_e)^2}$

Here $m_e$ is the mass of earth with value $m_e = 5.978 *10^{24} \ kg$

$r_e$ is the radius of the earth with value $r_e = 6371 \ km = 6371000 \ m$

G is the gravitational constant with value $G = 6.67 *10^{-11} \ m^3/ kg\cdot s^2$

$W = \frac{ 6.67 *10^{-11} * 70 * 5.978 *10^{24}}{ (275000 + 6371000)^2}$

$W = 631.92 \ N$

Converting to pounds

$W = \frac{631.92 }{4.45}$

$W = 142 \ lb$

7 0

2 years ago

an object is held 33.5 cm from a convex mirror. it creates a virtual image of magnification 0.253. what is the focal length of t

MaRussiya [10]

Answer:

Magnification= -image distance/object distance

.253=image distance/33.5

image distance= 8.48 cm

7 0

1 year ago

1. A car is traveling at 36 m/s hits a tree and comes to rest in 0.05 seconds.

QveST [7]

Answer: a. -720m/s^2

b. Yes, airbags will deploy

Explanation:

The formula for acceleration is:

= (Final velocity - Initial velocity)/Time

Final velocity = 0m/s

Initial velocity = 36m/s

Time taken = 0.05s

= (Final velocity - Initial velocity)/Time

= (0 - 36)/0.05

= -36/0.05

= -720m/s^2.

Since it's negative, it shows that there was a deceleration.

2. Yes the airbag will deploy since the acceleration gotten is more than -600 m/s^2.

3 0

3 years ago

Viruses use the energy of the ______ cells to reproduce themselves

galben [10]

<h2>Hey there!</h2>

<h2>The answer will be:</h2>

<h2>Explanation:</h2><h2 /><h3>Viruses use the energy of the <u>host</u> cells to reproduce themselves.</h3>

5 0

2 years ago

An airplane flies in a horizontal circle of radius 500 m at a speed of 150 m/s. If the radius were changed to 1000 m, but the sp

laila [671]

Answer:

The centripetal acceleration changed by a factor of 0.5

Explanation:

Given;

first radius of the horizontal circle, r₁ = 500 m

speed of the airplane, v = 150 m/s

second radius of the airplane, r₂ = 1000 m

Centripetal acceleration is given as;

$a = \frac{v^2}{r}$

At constant speed, we will have;

$v^2 =ar\\\\v = \sqrt{ar}\\\\at \ constant\ v;\\\sqrt{a_1r_1} = \sqrt{a_2r_2}\\\\a_1r_1 = a_2r_2\\\\a_2 = \frac{a_1r_1}{r_2} \\\\a_2 = \frac{a_1*500}{1000}\\\\a_2 = \frac{a_1}{2} \\\\a_2 = \frac{1}{2} a_1$

a₂ = 0.5a₁

Therefore, the centripetal acceleration changed by a factor of 0.5

7 0

3 years ago