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3 years ago

(1) Calculate the buoyant force on a 2.00-L helium balloon.

Physics

1 answer:

Mama L [17]3 years ago

6 0

Answer:

(1) 0.024 N

(2) 0.0093 N

Explanation:

When a body is immersed in a fluid partly of wholly it experience an upward force called buoyant force.

This buoyant force depends on the volume of the body, density of fluid and gravity.

(1) Volume = 2 L = 0.002 m^3

density of air, d = 1.23 kg/m^3

g = 9.8 m/s^2

The buoyant force is

F = V d g

F = 0.002 x 1.23 x 9.8 = 0.024 N

(2) mass, m = 1.5 g

The net vertical force is

F = F - m g

F = 0.024 - 0.0015 x 9.8 = 0.0093 N

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Answer:

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3 years ago

A sample has a density of 30 g/ml. there is 60 ml of this substance.how much does it weigh?

aleksandrvk [35]

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3 years ago

A 5.00-pF, parallel-plate, air-filled capacitor with circular plates is to be used in a circuit in which it will be subjected to

Nostrana [21]

Answer:

a) r=4.24cm d=1 cm

b) $Q=5x10^{-10} C$

Explanation:

The capacitance depends only of the geometry of the capacitor so to design in this case knowing the Voltage and the electric field

$V=1.00x10^{2}v\\E=1.00x10^{4} \frac{N}{C}$

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The distance must be the separation the r distance can be find also using

$C=\frac{Q}{V_{ab}}$

But now don't know the charge these plates can hold yet so

a).

d=0.01m

$C=E_{o}*\frac{A}{d}\\A=\frac{C*d}{E_{o}}$

$A=\frac{5pF*0.01m}{8.85x10^{-12}\frac{F}{m}}\\A=5.69x10^{-3}m^{2}$

$A=\pi *r^{2}\\r=\sqrt{\frac{A}{r}}\\r=\sqrt{\frac{5.64x10^{-3}m^{2} }{\pi } } \\r=42.55x^{-3}m$

b).

$C=\frac{Q}{V_{ab}}$

$Q=C*V\\Q=5x10^{-12} F*1x10^{2}\\Q=5x10^{-10}C$

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3 years ago

How to convert momentum into speed?

Firdavs [7]

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3 years ago

Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.0

IceJOKER [234]

Answer:

Explanation:

This is a case of interference of sound , akin to YDSE in optics .

Here, like interference dark and bright fringes, region of silence and intense sound will be formed due to destructive and constructive interference respectively.

Here d = distance between two sources = 5 m

D = distance of source and screen = 12m

position of first destructive interference

= λ D /2d

1 = λ 12 /2x 5

λ = 5 / 6 m

frequency = v / λ

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= 411.6 Hz

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3 years ago