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Rasek [7]
3 years ago
9

(1) Calculate the buoyant force on a 2.00-L helium balloon.

Physics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

(1) 0.024 N

(2) 0.0093 N

Explanation:

When a body is immersed in a fluid partly of wholly it experience an upward force called buoyant force.

This buoyant force depends on the volume of the body, density of fluid and gravity.

(1) Volume = 2 L = 0.002 m^3

density of air, d = 1.23 kg/m^3

g = 9.8 m/s^2

The buoyant force is

F = V d g

F = 0.002 x 1.23 x 9.8 = 0.024 N

(2) mass, m = 1.5 g

The net vertical force is

F = F - m g

F = 0.024 - 0.0015 x 9.8 = 0.0093 N

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If a hot air balloon has shown rising above the top of a hill, the top of the hill is considered as a reference point.

<h2>Reference Point:</h2>

It is a point that is used to standardize a experiment. The reference point is a constant point.

In the given problem:

  • The hot air balloon is rising above the top of the hill. Here, the hill is a standard point that has a fixed (constant) height.
  • Some other reference points are the top of the Eifel Tower or a famous shop which a person use to denote a certain distance.

Therefore, "If a hot air balloon has shown rising above the top of a hill" the top of the hill is considered as a reference point.

Learn more about Reference Point:

brainly.com/question/1674904

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The function h(t) = 162 +64t models the height, in feet, of a ball t seconds after it was kicked into the air. Which statement i
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3 years ago
A wire 3.22 m long and 7.32 mm in diameter has a resistance of 11.9 mΩ. A potential difference of 33.7 V is applied between the
Scorpion4ik [409]

Answer:

(a) Current is 2831.93 A

(b) 8.40A/m^2

(c) \rho =15.52\times 10^{-9}ohm-m

Explanation:

Length of wire l = 3.22 m

Diameter of wire d = 7.32 mm = 0.00732 m

Cross sectional area of wire

A=\pi r^2=3.14\times 0.00366^2=4.20\times 10^{-5}m^2

Resistance R=11.9mohm=11.9\times 10^{-3}ohm

Potential difference V = 33.7 volt

(A) current is equal to

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(B) Current density is equal to

J=\frac{i}{A}

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(c) Resistance is equal to

R=\frac{\rho l}{A}

11.9\times 10^{-3}=\frac{\rho \times 3.22}{4.20\times 10^{-5}}

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