<h2>
Answer:</h2>
Time
<h2>
Explanation:</h2>
The average speed of an object that is moving is defined as the distance traveled divided by the time of travel. You can measure the distance with a ruler and the time with a stopwatch. This can be expressed as the following formula:

For instance, if an object travels a distance
in 4 seconds, the the average speed is:

Answer:
Option (C)
Explanation:
Flash flood refers to the sudden flood that occurs in a particular area due to the heavy and excessive amount of rainfall, often accompanied by thunderstorms within a few hours. It releases a huge amount of water due to the failure of natural levee as well dam. They are very devastating. During flash flood, the water exerts a massive force which can make vehicles float over water. The <u>six inches of water</u> that flows over an area has the capacity to lift the tyres of small vehicles and carry hem further away.
Thus, the correct answer is option (C).
Answer:
The time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s is 0.84 seconds.
Explanation:
Given that,
Acceleration of the car, 
Initial speed of the car, u = 24.6 m/s
Final speed of the car, v = 26.8 m/s
We need to find the time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s. The acceleration of an object is given by :


t = 0.84 seconds
So, the time taken by the car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s is 0.84 seconds. Hence, this is the required solution.
The surface is frictionless, so there is no frictional force acting on the ball. There are no other forces acting on the ball in the horizontal direction, so it's a uniform motion with constant speed. Therefore, the velocity of the ball will remain the same for the entire duration of the motion, and so after 5 seconds the velocity is still 15 m/s.
Answer:
A. 91 meters north
Explanation:
Take +y to be north.
Given:
v₀ = 13 m/s
a = 0 m/s²
t = 7 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (13 m/s) (7 s) + ½ (0 m/s²) (7 s)²
Δy = 91 m
The displacement is 91 m north.