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3 years ago

Igneous rocks weather more easily than sedimentary rocks.

Physics

1 answer:

IrinaK [193]3 years ago

7 0

Answer:

False because igneous rocks are formed from a volcano and sedimentary never move they stay in one spot

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A system proposed by the U.S. Navy for underwater submarine communication, called ELF (for extremely low frequency), operates wi

kow [346]

Answer

Wavelength= 30*20^8/30=10^7m

Explanation:

Velocity = frequency *wavelength

We're frequency=30HZ

Velocity of light= 3*10^8m/s

Wavelength= 30*20^8/30=10^7m

Explanation:

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3 years ago

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How many licks dose it take to eat a lolipop

murzikaleks [220]

Answer: Around 364 to 480

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3 years ago

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Electromagnetic induction means that moving a magnet through a loop of wire creates an electric current.

MAVERICK [17]

False. An Electromagnetic induction is the production of an electromotive force across an electrical conductor in a changing magnetic field.

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3 years ago

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A cheetah can run at a maximum speed 97.8 km/h and a gazelle can run at a maximum speed of 78.2 km/h. If both animals are runnin

emmainna [20.7K]

(1)

Cheetah speed: $v_c = 97.8 km/h=27.2 m/s$

Its position at time t is given by

$S_c (t)= v_c t$ (1)

Gazelle speed: $v_g = 78.2 km/h=21.7 m/s$

the gazelle starts S0=96.8 m ahead, therefore its position at time t is given by

$S_g(t)=S_0 +v_g t$ (2)

The cheetah reaches the gazelle when $S_c=S_g$ . Therefore, equalizing (1) and (2) and solving for t, we find the time the cheetah needs to catch the gazelle:

$v_c t=S_0 + v_g t$

$(v_c -v_g t)=S_0$

$t=\frac{S_0}{v_c-v_t}=\frac{96.8 m}{27.2 m/s-21.7 m/s}=17.6 s$

(2) To solve the problem, we have to calculate the distance that the two animals can cover in t=7.5 s.

Cheetah: $S_c = v_c t =(27.2 m/s)(7.5 s)=204 m$

Gazelle: $S_g = v_g t =(21.7 m/s)(7.5 s)=162.8 m$

So, the gazelle should be ahead of the cheetah of at least

$d=S_c -S_g =204 m-162.8 m=41.2 m$

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3 years ago

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The space shuttle travels at a speed of about 7.6times10^3 m/s. The blink of an astronaut's eye lasts about 110 ms. How many foo

sveta [45]

Answer:

It covers distance of 9.15 football fields in the said time.

Explanation:

We know that

$Distance=Speed\times Time$

Thus distance covered in blinking of eye =

$Distance=7.6\times 10^{3}m/s\times 110\times 10^{-3}s\\\\Distance=836 meters$

Thus no of football fields= $\frac{936}{91.4}=9.15Fields$

7 0

2 years ago