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Scrat [10]
1 year ago
9

Which of the following statements explains why a race car going around a curve is accelerating, even if the speed is constant? A

. The car is accelerating because the magnitude as well as the direction of velocity is changing: B. The car is accelerating because the magnitude of velocity is changing: C. The car is accelerating because the direction of velocity is changing: D. The car is accelerating because neither the magnitude nor the direction of velocity is changing
Physics
1 answer:
Tom [10]1 year ago
7 0

OPTION C The car is accelerating because the direction of velocity is changing explains why a race car going around a curve is accelerating, even if the speed is constant

  • When a body is in uniform circular motion ( constant speed ), it will continuously cheanges its direction and so the body is accelerating
  • The rate at which an item changes its velocity is known as acceleration, a vector variable. If an object's velocity is changing, it is accelerating.
  • As a vector quantity, acceleration has a direction attached to it. The acceleration vector's direction is determined by two factors: if the thing is slowing down or speeding up the direction the thing is travelling in (+ or -)

  • The following general rule is used to calculate acceleration:

An object's acceleration will be in the opposite direction of its velocity if it is slowing down.

You may use this basic concept to determine if an object's acceleration is positive or negative, to the right or left, up or down, etc.

To know more about  acceleration visit : brainly.com/question/12550364

#SPJ4

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In the simulation above, as the projectile travels upward, how does the vertical velocity change? Question 9 options:
enot [183]

Answer:

Vertical velocity decreases.

Explanation:

The motion of the ball is a projectile ball, which consists of two independent motions:

- a horizontal motion, with constant velocity

- a vertical motion, with constant acceleration g=9.8 m/s^2 towards the ground

In the vertical motion, there is a constant acceleration directed downward: this means that the vertical velocity decreases as the ball goes higher. In fact, it decreases following the equation

v(t)=v_0 -gt

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4 0
3 years ago
The river narrows at a rapids from a width of 12 m to a width of only 5.8 m. The depth of the river before the rapids is 2.7 m;
Alisiya [41]

Answer:

7.89 m/s

Explanation:

Given that

Width of the river, b1 = 12 m

Width of the river, b2 = 5.8 m

Depth of the river, d1 = 2.7 m

Depth of the river, d2 = 0.85 m

Speed of the river, v1 = 1.2 m/s

Speed of the river, v2 = ?

Area of the river before the rapid, a1 = 12 * 2.7 = 32.4 m²

Area of the river after the rapid, a2 = 5.8 * 0.85 = 4.93 m²

To solve this question, we use a relation between the speed of the river and the volume of the river. We say,

Area1 * velocity1 = Area2 * velocity2, and when we substitute the values for each other we have

32.4 * 1.2 = 4.93 * v2

38.88 = 4.93v2

v2 = 38.88 / 4.93

v2 = 7.89 m/s

Therefore, the speed of the river after the rapid is 7.89 m/s

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