Charge of electron = 1.6×10−¹⁹
(1.6×10−¹⁹)(1×10²) (2e)
= 3.2×10−¹⁷ J
In a direct current, the electric charge, or current, only flows in one direction. In an alternating current, the electric charge changes periodically.
The bouncing person because the bounce helped him survive
Answer:
The acceleration of the proton is 2.823 x 10¹⁷ m/s²
The acceleration of the electron is 5.175 x 10²⁰ m/s²
Explanation:
Given;
distance between the electron and proton, r = 7 x 10⁻¹⁰ m
mass of proton,
= 1.67 x 10⁻²⁷ kg
mass of electron,
= 9.11 x 10⁻³¹ kg
The attractive force between the two charges is given by Coulomb's law;

where;
k is Coulomb's constant = 9 x 10⁹ Nm²/c²

Acceleration of proton is given by;
F = ma

Acceleration of the electron is given by;

Answer:
1027 N/C
3.42 x 10⁻⁶ T
Explanation:
I = Intensity of electromagnetic field = 1400 W/m²
E₀ = Maximum value of electric field
Intensity of electromagnetic field is given as
I = (0.5) ε₀ E₀² c
1400 = (0.5) (8.85 x 10⁻¹²) (3 x 10⁸) E₀²
E₀ = 1027 N/C
B₀ = maximum value of magnetic field
using the equation
E₀ = B₀ c
1027 = B₀ (3 x 10⁸)
B₀ = 3.42 x 10⁻⁶ T