All categories

3 years ago

A restaurant has $3,600 to spend on Advertising if each at Cost $600 how many ads will the restaurant be able to purchase

Mathematics

2 answers:

tekilochka [14]3 years ago

8 0

Answer: The restaurant will be able to purchase 6 ads.

Step-by-step explanation:

Hi, to answer this question we simply have to divide the money available for advertising ($3600) by the cost of each ad ($600).

Mathematically speaking:

$3600/ $600 per ad = 6 ads

In conclusion, the restaurant will be able to purchase 6 ads.

Feel free to ask for more if needed or if you did not understand something.

garri49 [273]3 years ago

5 0

Answer:

Step-by-step explanation:

If a restaurant has 3600 to spend on ads which costs 600 each, then they can buy 6 ads.

They can buy 6 ads since 3600/600 = 6.

You might be interested in

PLEASE HELP WILL GIVE BRAINLIEST AND 5.0 RATING

schepotkina [342]

Answer:

2.5, 4.5

Step-by-step explanation:

The x coordinate is 2.5 & the y coordinate is 4.5

5 0

2 years ago

The function f(x) = 2x + 210 represents the number of calories burned when exercising, where x is the number of hours spent exer

docker41 [41]

Hi,

f + g is a simple sum of the functions. This refers to increasing the good effect of exercise with diet effect, therefore more weight could be lost.

(f + g)(x) = f(x) + g(x) = 2x + 210 + 2x + 125 = 4x + 335, so (f + g)(x) = 4x + 335.

For x = 3 (meaning 3 hours of exercise) we have:

(f + g)(3) = 4·3 + 335 = 12 + 335 = 347 calories, after 3 hours of exercice.

The correct answer is: 347 calories burned while combining diet with 3 hours of exercise.

Have you understood ?

Green eyes.

3 0

3 years ago

If x + 3/4 =1, then which point on the number line could be x ?

Anni [7]

Answer:

point B

Step-by-step explanation:

isolate the x to solve for x:

=> x = 1 - $\frac{3}{4}$

=> x = $\frac{1}{4}$

point B=> the half of $\frac{1}{2}$ is $\frac{1}{4}$ => $\frac{1}{2}$ x $\frac{1}{2}$ = $\frac{1}{4}$

6 0

3 years ago

Read 2 more answers

What is the new volume of a right square pyramid with a volume 180in.3 if the lengths of the sides of the base remain fixed but

garik1379 [7]

The volume of a right square pyramid is $V= \frac{1}{3} A_{\text{ basis } }\cdot h$ , where $A_{\text{ basis } }$ is basis area.

If the lengths of the sides of the base remain fixed and height
is multiplied by a factor 10, than new height is $H=10h$ and the volume is

$V^{\ast}=A_{\text{ basis } }\cdot H=\frac{1}{3} A_{\text{ basis } }\cdot 10h=\frac{10}{3} A_{\text{ basis } }\cdot h$

7 0

3 years ago

Please help thank you

mamaluj [8]

Hm..I'm pretty sure the answer is 34

8 0

3 years ago