Ur answer in attachment hope it helps you
Answer:
The answer should be 8q-6 i think i tried
Step-by-step explanation:
We have
that
Cost
use of a backhoe----------------------$300 an hour
<span> Estimate for equipment rental each week---------------------$18,400</span>
Total
hours operator per week--------------------------------------40
<span> 40*300</span>=$12000---------------------it
is the cost per week to use a backhoe
$12000<$18400 is ok
<span> The maximum of hours that I can rent </span>a backhoe <span> are 40 hours, since it is the limit of the
operator and it do not overcome the total budget </span>
Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Answer:
w = 9
Step-by-step explanation:
18 + 4w = 6w
6w - 4w = 2w
2w = 18
18/2 = 9
2w/2 = w
w = 9
