Answer: 151.305 kg
Step-by-step explanation:
0.300μg = 0.3x10⁻⁶ g/l
mass in kg?
Volume of lake = surface area * depth
surface area = 13mi²
depth = 49 ft
<u>Feet to miles</u>
49 ft → mi = 0.00928 mi
(1 mi = 5280 ft)
V = 13*0.00928 = 0.121 mi³
<u>cubic Miles to cubic meters</u>
1mi³ = 4168182000 m³
0.121 mi³ = 504350022 m³
<u>Cubic meters to liters</u>
1L = 1000 m³
Lake has 5.04350022x10¹¹ L
Concentration = 0.3x10⁻⁶ g/l
Lake has 151305 g of Hg = 151.305 kg of Hg
Answer:
m = 4
Step-by-step explanation:
Substitute x = 1, y = 1 , that is(1,1) into the equation
1 - 5 = m(1 - 2)
- 4 = - m ( multiply both sides by - 1 )
m = 4
Answer:
x= 6
Step-by-step explanation:
12+3x=30
3x+12=30
3x+12-12=30-12
3x=30-12
3x=18
3x divided by 3 = 18 divided by 3
x=18 over 3
18 divided by 3 is 6
x=6
Answer:
I beileve its no
Step-by-step explanation:
