Answer:
B. 10m/s
Explanation:
If a drone flies 8 m/s due East with respects to the wind and the wind is blowing 6 m/s due North, the speed of the drone with respect to the ground is its displacement.
Displacement is calculated using Pythagoras theorem.
d² = 8²+6²
d² = 64+36
d² = 100
Square root both sides
√d² = √100
d = 10m/s
Hence the distance of the drone with respect to the ground is 10m/s
Option B is correct
Explanation:
Let us assume that the mass of a pitched ball is 0.145 kg.
Initial velocity of the pitched ball, u = 47.5 m/s
Final speed of the ball, v = -51.5 m/s (in opposite direction)
We need to find the magnitude of the change in momentum of the ball and the impulse applied to it by the bat. The change in momentum of the ball is given by :
![\Delta p=m(v-u)\\\\\Delta p=0.145\times ((-51.5)-47.5)\\\\\Delta p=-14.355\ kg-m/s](https://tex.z-dn.net/?f=%5CDelta%20p%3Dm%28v-u%29%5C%5C%5C%5C%5CDelta%20p%3D0.145%5Ctimes%20%28%28-51.5%29-47.5%29%5C%5C%5C%5C%5CDelta%20p%3D-14.355%5C%20kg-m%2Fs)
So, the magnitude of the change in momentum of the ball is 14.355 kg-m/s.
Let the the ball remains in contact with the bat for 2.00 ms. The impulse is given by :
![J=\dfrac{\Delta p}{t}\\\\J=\dfrac{14.355}{2\times 10^{-3}}\\\\J=7177.5\ kg-m/s](https://tex.z-dn.net/?f=J%3D%5Cdfrac%7B%5CDelta%20p%7D%7Bt%7D%5C%5C%5C%5CJ%3D%5Cdfrac%7B14.355%7D%7B2%5Ctimes%2010%5E%7B-3%7D%7D%5C%5C%5C%5CJ%3D7177.5%5C%20kg-m%2Fs)
Hence, this is the required solution.
Acceleration is the way the motion is changing.
Explanation:
Work is the product of force and distance.
W = F×d
W = (22 N) × (16 m)
W = 352 J
C :) cause a direction has nothing do do with velocity !