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2 years ago

How does kinetic energy connect or relate to Newtons second law of motion?

2 answers:

8 0

Newtons second law of motion: "T<span>he acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object."

kinetic energy is energy that an object posses while in motion and to get that it must have potential energy.</span>

Darya [45]2 years ago

7 0

The second law of motion is: <em>"Force equals mass times acceleration"</em>. Newton’s first law says that a net external force results in a change in motion; thus, we see that a net external force causes acceleration, which is <em>"the rate of change of velocity per unit of time"</em>. In physics, the kinetic energy of an object is the energy that it possesses due to its motion and it is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. So Kinetic energy is somewhat related to acceleration which is used in Newton's second law of motion.

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You and a friend both leave the same restaurant to drive home. You are heading directly west at 30 miles per hour and he or she

steposvetlana [31]

Answer:

$\frac{dAB}{dt} = = 50 miles/ hour$

Explanation:

let A represent me and B represent my friend

A speed $\frac{dOA}{dt}$ =30 m/hr toward west

B speed $\frac{dOB}{dt}$ =40 m/hr toward south

after 1/2 hr

total distance cover by A =1/2 * 30 miles = 15 miles

total distance by B = 1/2*40 miles = 20 miles

now from figure

$AB = \sqrt{(15^2+20^2)} = 25 miles$

$AB^2 =OA^2+ OB^2$

Differentiate above equation

$2AB\frac{dAB}{dt} = 2OA\frac{dOA}{dt} +2OB\frac{dOB}{dt}$

$25*\frac{dAB}{dt} = 15*30 +20*40$

$\frac{dAB}{dt} = \frac{1250}{25}$

$\frac{dAB}{dt} = = 50 miles/ hour$

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3 years ago

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Can you help me with this physics homework? please

KengaRu [80]

Answer:

Area under a curve can be estimated via block counting, calculated with simple geometry if the velocity has constant accelerations, or calculated by integration if the velocity can be described by a mathematical equations.

The area under a velocity time curve will be the product of velocity and time which equals displacement.

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2 years ago

What are the steps of the scientific method?

Annette [7]

The steps are;
1- make an observation
2- ask questions
3- form a hypothesis
4- conduct an experiment
5- accept or reject your hypothesis

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2 years ago

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Traveling into space from Earth, which of these would he be able to reach first?

mr Goodwill [35]

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2 years ago

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A horizontal pipe of inner diameter 2.2 cm carries water with a density of 1000.0 kg/m3 flowing at a rate of 1.5 kg/s. If the pi

EleoNora [17]

The speed of the water in the wider part will be 1.194 m/sec. Speed is a time-based quantity. Its SI unit is m/sec.

<h3> What is speed?</h3>

Speed is defined as the rate of change of the distance or the height attained.

The given data in the problem is;

The initial diameter is, $\rm d_1 = 2.2 \ cm$

initial radius,

$r_1 = \frac{d_1}{2} \\\\ r_1 = \frac{2.2}{2} \\\\ r_1 = 1.1\ cm$

The initial crossection area;

$\rm A_1 = \pi r_1^2 \\\\ \rm A_1 = 3.14 \times (1.1\times 10^{-2})^2 \\\\ \rm A_1 =3.8 \times 10^{-4} \ m^2$

The final crossection area;

$\rm A_2 = \pi r_2^2 \\\\ \rm A_2 = 3.14 \times ( 2 \times 10^{-2})^2 \\\\ \rm A_2 = 12.56 \ m^2$

The initial flow rate is;

R = density ×velocity ×area

$\rm R = \rho A V \\\\ 1.5 = 1000 \times V_1 \times 3.8 \times 10^{-4} \\\\ V_1 = 3.947 \ m/sec$

The speed of the water in the wider part will be;

From the continuity equation;

$\rm A_1 V_1 = A_2V_2 \\\\\ 3.8 \times 10^{-4} \times 3.947 = 12.56 \times 10^{-4} \times V_2 \\\\ V_2= 1.194 \ m/sec$

Hence, the speed of the water in the wider part will be 1.194 m/sec.

To learn more about the speed, refer to the link;

brainly.com/question/7359669

#SPJ1

7 0

1 year ago