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lana66690 [7]
3 years ago
9

How does kinetic energy connect or relate to Newtons second law of motion?

Physics
2 answers:
Orlov [11]3 years ago
8 0
Newtons second law of motion: "T<span>he acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object."

kinetic energy is energy that an object posses while in motion and to get that it must have potential energy.</span>
Darya [45]3 years ago
7 0

The second law of motion is: <em>"Force equals mass times acceleration"</em>. Newton’s first law says that a net external force results in a change in motion; thus, we see that a net external force causes acceleration, which is <em>"the rate of change of velocity per unit of time"</em>. In physics, the kinetic energy of an object is the energy that it possesses due to its motion and it is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. So Kinetic energy is somewhat related to acceleration which is used in Newton's second law of motion.

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If the mass of the body is doubled what should be its speed so as to maintain the same kinetic energy ?​
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The speed should be reduced by 1/√2 or 0.707 times

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The relationship between the kinetic energy, mass and velocity can be represented by the following equation:

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In this equation, the mass is inversely proportional to the square of the velocity or speed. This means that as the mass increases, the speed reduces by × 2.

Let; initial mass = m1

Final mass = m2

Initial velocity = v1

Final velocity = v2

According to the question, if the mass of the body is doubled i.e. m2 = 2m

½m1v1² = ½m2v2²

½ × m × v1² = ½ × 2m × v2²

Multiply both sides by 2

(½ × m × v1²)2 = (½ × 2m × v2²)2

m × v1² = 2m × v2²

Divide both sides by m

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Divide both sides by 2

v1²/2= v2²

Square root both sides

√v1²/2= √v2²

v1/√2 = v2

v2 = 1/√2 v1

This shows that to maintain the same kinetic energy if the mass is doubled, the speed should be reduced by 1/√2 or 0.707 times.

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