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tatiyna
2 years ago
14

If a machine will do 50 J of work in 35 seconds how much power did it produce?

Physics
1 answer:
grandymaker [24]2 years ago
6 0
Power is the amount of work done over a period of time. If you will put that into an equation, the formula of power will be:

P = W/t
Where:
P = power
W=work
t = time

Your problem already provides you with work and time so all you need to do is divide:

P = W/t
P = 50J/30s
P = 1.67 W
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Mr. Barcena reached a top speed of 5m/s in 2 seconds from rest, what was his average acceleration including units?
sashaice [31]

Answer:

Explanation:

The equation for acceleration is

a=\frac{v_f-v_0}{t} where vf is the final velocity and v0 is the initial velocity. Filling in:

a=\frac{5-0}{2} so

a = 2.5 m/s/s

4 0
2 years ago
Gantt charts are A. widely used network techniques. B. not widely used. C. planning charts used to schedule resources and alloca
kotykmax [81]

Answer:

planning charts used to schedule resources and allocate time is the correct answer

Explanation:

  • Gantt Charts are a project planning tool used to track the projects from the start to endpoint.
  • Gantt charts are used for the preparation and planning of the projects.
  • By using Gantt charts we can assess how much time a project would take to complete and we can also determine resources required with the help of Gantt charts.

6 0
3 years ago
The kinetic theory states that the higher the temperature, the faster the
max2010maxim [7]

Answer: the higher the kinetic energy

Explanation:

4 0
2 years ago
Suppose that the dipole moment associated with an iron atom of an iron bar is 2.8 × 10-23 J/T. Assume that all the atoms in the
masya89 [10]

To solve this exercise it is necessary to apply the equations related to the magnetic moment, that is, the amount of force that an image can exert on the electric currents and the torque that a magnetic field exerts on them.

The diple moment associated with an iron bar is given by,

\mu = \alpha *N

Where,

\alpha = Dipole momento associated with an Atom

N = Number of atoms

\alpha y previously given in the problem and its value is 2.8*10^{-23}J/T

L = 5.8cm = 5.8*10^{-2}m

A = 1.5cm^2 = 1.5*10^{-4}m^2

The number of the atoms N, can be calculated as,

N = \frac{\rho AL}{M_{mass}}*A_n

Where

\rho = Density

M_{mass} = Molar Mass

A = Area

L = Length

A_n =Avogadro number

N = \frac{(7.9g/cm^3)(1.5cm)(5.8cm^2)}{55.9g/mol}(6.022*10^{23}atoms/mol)

N = 7.4041*10^{23}atoms

Then applying the equation about the dipole moment associated with an iron bar we have,

\mu = \alpha *N

\mu = (2.8*10^{-23})*(7.4041*10^{23})

\mu = 20.72Am^2

PART B) With the dipole moment we can now calculate the Torque in the system, which is

\tau = \mu B sin(90)

\tau = (20.72)(2.2)

\tau = 45.584N.m

<em>Note: The angle generated is perpendicular, so it takes 90 ° for the calculation made.</em>

3 0
3 years ago
Can there be situation when velocity is constant but speed is not
klasskru [66]

Answer:

no I don’t think there can be so my answer is No.

Okay then yes sorry that I must have gotten it wrong before.

Explanation:

4 0
2 years ago
Read 2 more answers
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