Use TrianCal to draw a triangle with phi as Great Piramid (minimum perimeter given 2 equal heights) = maximun stability.
NOTE: Phi=(1+√5)/2≈1.62 and acos(1/Phi)≈51.83º
Set the number of chickens as x and number of cows as <span>y
</span>so the farmer has total 28 animals
so x+y=28
you know that since the animals are healthy
chickens will have 2 legs and
cows will have 4 legs
the total number of legs are 64
so 2x+4y=64
since you want to find the number of cows
so from the first equation <span>x+y=28
</span>we will get another equation <span>x=28-y
</span>then plug into <span>2x+4y=64
2(28-y)+4y=64
56-2y+4y=64
56+2y=64
-56 -56
2y=8
y=4
</span>
Answer: 9 Apples
Step-by-step explanation:
Given the following :
Total number of bags = 12
Mean of the distribution(m) = 8
Number of apples (x):
6 - - - - 7 - - - - 8 - - - - 9 - - - - 10
Frequency (f) :
1 - - - - 4 - - - - 2 - - - - 3 - - - - 1
Therefore :
Let number of apples in the 12th bag = y
Frequency of 12th bag : (12 - 11) = 1
Mean of distribution(m) :
Sum of ( f * x) / sum of f
Sum of (f * x) = (6*1)+(7*4)+(8*2)+(9*3)+(10*1)+(y*1)
Sum of (f * x) = (6+28+16+27+10+y) = 87 + y
Sum of f = 12
From :
m = Sum of ( f * x) / sum of f
8 = (87 + y) / 12
87 + y = 12 * 8
87 + y = 96
y = 96 - 87
y = 9
Number of apples in 12th bag is 9 apples
I think it’s A hope that helped
- Principle=P=470
- Time=T=10
- Rate =R=R=9%
Interest be I
If interest is daily
- I=PRT/100
- I=470(10)(9)/100
- I=4230/10
- I=423$
If interest is monthly (30days)
- I=(470)(1/3)(9)/100
- I=470(3)/100
- I=1410/100
- I=14.10$
