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lorasvet [3.4K]
3 years ago
9

Black vultures excel at gliding flight; they can move long distances through the air without flapping their wings while undergoi

ng only a modest drop in height. A vulture in a typical glide in still air moves along a path tipped 3.5∘ below the horizontal. If the vulture moves a horizontal distance of 100 m, how much height does it lose?
Physics
1 answer:
GenaCL600 [577]3 years ago
4 0

Answer:

The vulture loses 6.1 m height

Explanation:

Please see the attached figure.

The horizontal distance and the loss of height form a 90º triangle.

The loss of height is  the side opposite the given angle (3.5º) and the 100 m horizontal distance is adjacent the angle.

Then, using trigonometric rules:

(1)   sin 3.5º = h / hyp

(2)  cos 3.5º = distance / hyp

where

h = height lost during the flight.

hyp = hypotenuse of the triangle

Using (2) we can calculate the hypotenuse:

cos 3.5º = 100 m / hyp

hyp = 100 m / cos 3.5º = 100.2 m

with the hypotenuse we can now calculate the loss of height using (1):

sin 3.5º = h / hyp

sin 3.5º = h / 100.2 m

sin 3.5º * 100.2 m = h

<u>h = 6.1 m</u>

( very modest drop in height indeed!)

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A 20-Kg child is on a swing attached to 3.0 m-long chains. The child swings back and forth, swinging out to a 60-degree angle. (
kvv77 [185]

Answer:

 v = 29.4 m / s

Explanation:

For this exercise we can use the conservation of mechanical energy

Lowest starting point.

          Em₀ = K = ½ m v²

final point. Higher

          Em_{f} = U = m g h

Let's use trigonometry to lock her up

          cos 60 = y / L

          y = L cos 60

Height is the initial length minus the length at the maximum angle

           h = L - L cos 60

           h = L (1- cos 60)

energy is conserved

         Em₀ = Em_{f}

          ½ m v² = mgL (1 - cos 60)

         v = 2g L (1- cos 60)

 

let's calculate

          v² = 2 9.8 3.0 (1- cos 60)

          v = 29.4 m / s

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