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shusha [124]
3 years ago
14

Please help answer questions 1-4. Show your work.

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

1) V = a × t, where v is the velocity, a is the acceleration and t is the time

2) Vf - Vi = a × t

So 1.3 - 1.1 = a × 20

a = 0.01 m/s²

3) Vf - Vi = a × t

0 - 2 = a × 3

a = -2/3 m/s²

4) If an object is slowing down, the acceleration is negative and vice versa.

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.A box falls to the ground from a delivery truck traveling at 30 m/s. After hitting the road, it slides 45 m to
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Answer:

t = 3 seconds

Explanation:

Given that,

Initial speed, u = 30 m/s

Final speed, v = 0

It slides 45 m to rest.it take the box to come to rest

We need to find how long it take the box to come to rest.

Let a be the acceleration and t is time.

v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(30)^2-u^2}{2(45)}\\\\=10\ m/s^2

Now finding time.

t=\dfrac{v-u}{a}\\\\t=\dfrac{30-0}{10}\\\\t=3\ s

So, the required time is 3 seconds.

8 0
3 years ago
Did I do these questions correctly?
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Yes, they seem right to me.
4 0
4 years ago
What decibel level can cause hearing damage to begin
densk [106]

Answer: Noise above 70 dB can cause hearing damage

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Determine the net work a hiker must do on a 3.35-kg backpack to carry it up a
Sphinxa [80]

Answer:

410.4J

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8 0
3 years ago
The instruction booklet for your pressure cooker indicates that its highest setting is 12.3 psi . you know that standard atmosph
zmey [24]
<span>118 C The Clausius-Clapeyron equation is useful in calculating the boiling point of a liquid at various pressures. It is: Tb = 1/(1/T0 - R ln(P/P0)/Hvap) where Tb = Temperature boiling R = Ideal Gas Constant (8.3144598 J/(K*mol) ) P = Pressure of interest Hvap = Heat of vaporization of the liquid T0, P0 = Temperature and pressure at a known point. The temperatures are absolute temperatures. We know that water boils at 100C at 14.7 psi. Yes, it's ugly to be mixing metric and imperial units like that. But since we're only interested in relative pressure differences, it's safe enough. So P0 = 14.7 P = 14.7 + 12.3 = 27 T0 = 100 + 273.15 = 373.15 And for water, the heat of vaporization per mole is 40660 J/mol Let's substitute the known values and calculate. Tb = 1/(1/T0 - R ln(P/P0)/Hvap) Tb = 1/(1/373.15 K - 8.3144598 J/(K*mol) ln(27/14.7)/40660 J/mol) Tb = 1/(0.002679887 1/K - 8.3144598 1/K ln(1.836734694)/40660) Tb = 1/(0.002679887 1/K - 8.3144598 1/K 0.607989372/40660) Tb = 1/(0.002679887 1/K - 5.055103194 1/K /40660) Tb = 1/(0.002679887 1/K - 0.000124326 1/K) Tb = 1/(0.002555561 1/K) Tb = 391.3034763 K Tb = 391.3034763 K - 273.15 Tb = 118.1534763 C Rounding to 3 significant figures gives 118 C</span>
3 0
3 years ago
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