All categories

4 years ago

How much total work is done by the force in lifting the elevator from 0.0 m to 9.0 m?

Physics

1 answer:

aksik [14]4 years ago

8 0

The total work is

(mass of the elevator, kg) x (9.8 m/s²) x (9.0 m) Joules .

You might be interested in

8. John has to hit a bottle with a ball to win a prize. He throws a 0.4 kg ball with a velocity of 18 m/s. It hits a 0.2 kg bott

nasty-shy [4]

Answer: The ball is travelling with a speed of 5.5 m/s after hitting the bottle.

Explanation:

To calculate the speed of ball after the collision, we use the equation of law of conservation of momentum, which is given by:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

where,

$m_1,u_1\text{ and }v_1$ are the mass, initial velocity and final velocity of ball.

$m_2,u_2\text{ and }v_2$ are the mass, initial velocity and final velocity of bottle.

We are given:

$m_1=0.4kg\\u_1=18m/s\\v_1=?m/s\\m_2=0.2kg\\u_2=0m/s\\v_2=25m/s$

Putting values in above equation, we get:

$(0.4\times 18)+(0.2\times 0)=(0.4\times v_1)+(0.2\times 25)\\\\v_1=5.5m/s$

Hence, the ball is travelling with a speed of 5.5 m/s after hitting the bottle.

5 0

3 years ago

A 70 watt light bulb is run by a 120 v circuit. how many amps does it use

Marizza181 [45]

Current = Power/Voltage. 70W/120v= 0.583 Amps.

6 0

4 years ago

Hello Please Help With A couple Science questions

matrenka [14]

#1 A) Long wavelength and high frequency.

#2) A) Brightness.

#3) D) They are used to examine things.

#4) B) Compression and visible light waves.

5 0

3 years ago

Read 2 more answers

The surface area of a material is a factor that affects heat conductivity. Does heat flow faster through a large surface area or

Elis [28]

The air flows slower in a bigger space. The air in a small space hit each other heating up, and move faster and faster. is that what your asking?

4 0

3 years ago

A 2,000 kg rocket is launched 12 km straight up at a constant acceleration into the sky at which point the rocket is travelling

iogann1982 [59]

Answer:

797700000 J

Explanation:

From the question,

The work done by the rocket, is given as,

W = Ek+Ep............. Equation 1

Where Ek and Ep are the potential and the kinetic energy of the rocket respectively.

Ep = mgh............ Equation 2

Ek = 1/2mv²............. equation 3

Substitute equation 2 and equation 3 into equation 1

W = mgh+1/2mv².............. Equation 4

Where m = mass of the rocket, h = height, v = velocity of the rocket, g = acceleration due to gravity.

Given: m = 2000 kg, h = 12 km = 12000 m, v = 750 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 2000(12000)(9.8)+1/2(2000)(750²)

W = 235200000+562500000

W = 797700000 J

6 0

3 years ago