What happens when solving this with a 0 on the outside of the “()”?

Mathematics

1 answer:

ella [17]3 years ago

7 0

Anything to the zeroth power equals 1, so

$(32 x^{11} y^9)^0 = 1$

You might be interested in

Find the area of the shaded region in square units. Show your reasoning.

motikmotik

Answer:

40 square units

Step-by-step explanation:

First of all, lets say that square has side $l$ , so, the area unit is $l^2$

the diagonal's square is $l\sqrt{2}$

CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)

$A_{triangles}=4*base*heigh*0.5=2*(l\sqrt{2} )(2l\sqrt{2} )=8l^2$

CALCULATION OF MAIN SQUARE AREA

$A_{square}=side*side=(4\sqrt{2} l)(4\sqrt{2} l)=32l^2$

TOTAL AREA

$A_{total}=A_{triangles}+A_{square}=8l^2+32l^2=40l^2$

3 0

3 years ago

My questions are in the picture please help

Marrrta [24]

21.

So to solve for the value of a variable in an equation, you would need to isolate x on one side. The first thing you have to do is multiply 2 and (x + 7) together, which can be rewritten as 2(x) + 2(7). After multiplying, your equation would be: $2x+14+3x=12$ , or A.

22.

So the rule with multiplying exponents with the same base is to add the exponents together, and the rule with dividing exponents with the same base is to subtract the exponents. Your equation will be simplified as such:

$4^{(3+4)-9}\\ 4^{7-9}\\ 4^{-2}$

Now the rule with converting negative exponents into fractions is $x^{-m}=\frac{1}{x^m}$ . In this case, 4^-2 would turn into $\frac{1}{4^2}$ , or C, which is your final answer.