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lakkis [162]
3 years ago
9

A line has a slope of -1/2 and a y-intercept of –2. So what is the x intercept on the line.

Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

(4,0)

Step-by-step explanation:

The equation of the line is y = (-1/2)x - 2.  At the x-intercept, y = 0. Setting y = (-1/2)x - 2 to zero, we get (1/2)x = 2, and thus x = 4.  

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Answer:

Side-Side-Side (SSS) Congruence Property

Step-by-step explanation:

Congruence just means that two things are of the same size. For instance, if you have two congruent side lengths, they are the same length. In this picture, you can see that both triangles have a side with one dash and a side with two dashes. In geometry, to show that two lines are congruent you give them the same number of dashes, and therefore you know for sure that those two pairs of sides are congruent. Finally, the triangles share a side length, so you know that that side length is equal for them. Therefore, the appropriate congruence property here is SSS, since you know that three pairs of sides are congruent.

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3 years ago
What is 214729.08 rounded to nearest thousand
nata0808 [166]
Hello!!

214,729.08 rounded to nearest thousand is 215,000.

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4 0
4 years ago
Write the equation of the line that passes through (0, 3) and is parallel to the line 3x + 5y = 6.
Sunny_sXe [5.5K]
There's more ways than one to solve this, just as there's more ways than one to skin a cat.

Two paralle lines have the same slope, so the desired new line looks exactly like the given line 3x + 5y = 6, except that the constant, 6, is replaced by another value.

Write out 3x + 5y = c
Replace x with 0 and y with 3.  Then 3(0) + 5(3) = c, and c = 15.

Thus, the equation of the new, parallel, line is 3x + 5y = 15.
7 0
3 years ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

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C  a rectangle. brainily says this is too short so I am writing more 
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