Okay your answer is 1 I think
From ideal gas equation that is pv =nRt
n=number of moles which can be written as the ratio between the weight of a gas that is mass and its molecular mass n=m/Mm
pv=(m/Mm)RT
density is=mass per unit volume
P=m/v by arranging the equation we get
R =0.082atm/mol/k
Mm=pRT/P=[(1.10 x10^-6 x1000g/l) xo.082 atm/mol/k x(80+273] /(1.00 x10^-3) =31.84 to the nearest ten is 32
hence the gas is oxygen
Li because its charge is +1.
Answer:
7.5 M
Explanation:
In order to find a solution's molar concentration, or molarity, you need to determine how many moles of solute, which in your case is sodium sulfate,
Na
2
SO
4
, you get in one liter of solution.
That is how molarity was defined -- the number of moles of solute in one liter of solution.
So, you know that you have
0.090
moles of solute in
12 mL
of solution. Your goal here will be to scale up this solution by using this information as a conversion factor to help you determine the number of moles of solute present in
