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MatroZZZ [7]
3 years ago
15

a compound with the empirical formula CH2 has a molar mass of 112 g/mol. What is the molecular formula for this compound?

Chemistry
1 answer:
miv72 [106K]3 years ago
5 0
Hope it cleared your doubt :-D

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A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.50 grams of aluminum foil in a solut
Irina-Kira [14]

Answer:

Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.

Explanation:

  • It is a stichiometry problem.
  • We should write the balance equation of the mentioned chemical reaction:

<em>2Al + 3CuCl₂ → 3Cu + 2AlCl₃.</em>

  • It is clear that 2.0 moles of Al foil reacts with 3.0 moles of CuCl₂ to produce 3.0 moles of Cu metal and 2.0 moles of AlCl₃.
  • Also, we need to calculate the number of moles of the reported masses of Al foil (0.50 g) and CuCl₂ (0.75 g) using the relation:

<em>n = mass / molar mass</em>

  • The no. of moles of Al foil = mass / atomic mass = (0.50 g) / (26.98 g/mol) = 0.0185 mol.
  • The no. of moles of CuCl₂ = mass / molar mass = (0.75 g) / (134.45 g/mol) = 5.578 x 10⁻³  mol.
  • <em>From the stichiometry Al foil reacts with CuCl₂ with a ratio of 2:3.</em>

∴ 3.85 x 10⁻³  mol of Al foil reacts completely with 5.578 x 10⁻³  mol of CuCl₂ with <em>(2:3)</em> ratio and CuCl₂ is the limiting reactant while Al foil is in excess.

  • From the stichiometry 3.0 moles of  CuCl₂ will produce the same no. of moles of copper metal (3.0 moles).
  • So, this reaction will produce 5.578 x 10⁻³ mol of copper metal.
  • Finally, we can calculate the mass of copper produced using:

mass of Cu = no. of moles x Atomic mass of Cu = (5.578 x 10⁻³  mol)(63.546 g/mol) = 0.354459 g ≅ 0.36 g.

  • <u><em>So, the answer is:</em></u>

<em>Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.</em>

5 0
4 years ago
effect. RbClO(s) → Rb+(aq) + ClO−(aq) HClO(aq) + H2O(l) equilibrium reaction arrow H3O+(aq) + ClO−(aq) The degree of dissociatio
Lemur [1.5K]

Explanation:

Common ion effect is defined as the effect which occurs on equilibrium when a common ion (an ion which is already present in the solution) is added to a solution. This effect generally decreases the solubility of a solute.

Equilibrium reaction of strontium sulfate and sodium sulfate follows the equation:

RbClO(s)\rightarrow Rb^{+}(aq.)+ClO^{-}(aq.)

HClO(aq)+H_2O\rightleftharpoons H_3O^+(aq.)+ClO^{-}(aq.)

According to Le-Chateliers principle: If there is any change in the variables of the reaction, the equilibrium will shift in the direction in order to minimize the effect.

In the equilibrium reactions, hypochlorite ion is getting increased on the product side, so the equilibrium will shift in the direction to minimize this effect, which is in the direction of hydrogen hypochlorite.

Thus, the addition hypochlorite ions will shift the equilibrium in the left direction.

The dissociation of hydrogen hypochlorite is suppressed due to the common ion effect.

8 0
3 years ago
Lithium metal reacts with nitrogen gas to form lithium nitride. identify the balanced reaction that describes this process
Arlecino [84]

Lithium metal reacts with nitrogen gas to form lithium nitride the balanced chemical equation will be 6Li + N₂ → 2Li₃N.

<h3>What is a balanced chemical reaction?</h3>

In a balanced chemical reaction, the number of moles that are present at the side of the reactant must be always equal to the side of product formation this is known as a balanced chemical equation.

The balanced chemical reaction will be 6Li + N₂ → 2Li₃N.

Here 6 moles of lithium is reacting with one nitrogen but as it is in gaseous state it is N₂ after reacting with lithium it will give two moles

Therefore, balanced equation will be 6Li + N₂ → 2Li₃N

Learn more about balanced chemical reaction, here :

brainly.com/question/15178192

#SPJ4

6 0
1 year ago
Yes carbohydrates have both monomers and polymers. Monomers of carbohydrates are monosaccharides (mono- one; saccharide- sugar)
GenaCL600 [577]

Answer:

Ok. so what's the question .-.

Explanation:

4 0
3 years ago
Read 2 more answers
Suppose that 10.1 mL of HNO3 is neutralized
Vedmedyk [2.9K]

Answer:

0.0251 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

The mole ratio of the acid (nA) = 1

The mole ratio of the base (nB) = 1

Next, the data obtained from the question. This include the following:

Volume of acid (Va) = 10.1mL

Molarity of acid (Ma) =..?

Volume of base (Vb) = 61.9 mL

Molarity of base (Mb) = 0.0041 M

Next, we shall determine the molarity of the acid, HNO3 as follow:

MaVa/MbVb = nA/nB

Ma x 10.1 / 0.0041 x 61.9 = 1

Cross multiply to express in linear form

Ma x 10.1 = 0.0041 x 61.9

Divide both side by 10.1

Ma = (0.0041 x 61.9) /10.1

Ma = 0.0251 M

Therefore, the molarity of HNO3 is 0.0251 M

6 0
3 years ago
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