All categories

3 years ago

a compound with the empirical formula CH2 has a molar mass of 112 g/mol. What is the molecular formula for this compound?

Chemistry

1 answer:

miv72 [106K]3 years ago

5 0

Hope it cleared your doubt :-D

You might be interested in

How can you use continental drift hypothesis in a sentence

AveGali [126]

Answer:

The largest bays have developed as a result of continental drift. With the loss of either of these, continental drift will come to a halt

Explanation:

4 0

2 years ago

If 0.500 mol of NaN3 react what mass I'm grams of nitrogen would result

klemol [59]

Looks like 3*.5 mol of N, or 1.5*.5 N2
convert that to grams.

6 0

3 years ago

When sugar dissolves in water are covalent bonds broken?

Amanda [17]

Gle's cache of http://www.middleschoolchemistry.com/lessonplans/chapter5/lesson4. It is a snapshot of the page as it appeared on 21 Oct 2017 07:24:57 GMT.

7 0

3 years ago

Is carbon a metal or a nonmetal? How many valence electrons does a carbon atom have?

marshall27 [118]

Answer:

Carbon is a solid non-metal element. Carbon has eight valence electrons.

Explanation:

hope this helps!

7 0

3 years ago

A sample of argon gas has a volume of 795 mL at a pres-sure of 1.20 atm and a temperature of 116 ∘C. What is the final volume of

jek_recluse [69]

Answer: The volume when the pressure and temperature has changed is $1.6\times 10^2mL$

Explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

Let us assume:

$P_1=1.20atm\\V_1=795mL\\T_1=116^oC=[116+273]K=389K\\P_2=0.55atm\\V_2=?mL\\T_2=75^oC=[75+273]K=348K$

Putting values in above equation, we get:

$\frac{1.20atm\times 795mL}{389K}=\frac{0.55atm\times V_2}{348K}\\\\V_2=\frac{1.20\times 795\times 348}{0.55\times 389}=1.6\times 10^3mL$

Hence, the volume when the pressure and temperature has changed is $1.6\times 10^2mL$

5 0

2 years ago