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3 years ago

Please help!!! will give brainliest!!! 30 points! (need to put roman numeral in answer)

Chemistry

1 answer:

mariarad [96]3 years ago

3 0

1. Nickel (II) Bromide

2. Iron (II) Oxide

3. Iron (III) Oxide

4. Tin (IV) Chloride

5. Lead (IV) tetrachloride

6. Tin (II) Bromide

7. Chromium (III) Phosphide

8. Iron (II) Fluoride

9. Gold (III) Chloride

I hope this helps. I'm more than 100% sure that all the answers except for number 7 are correct. I knew all of them off the top of my head except for this one. I hope the other answer has the correct answer for that one. Good luck and have a great day.

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Which aldehyde is an intermediate in the reduction of ethyl benzoate with lithium aluminum hydride?

garri49 [273]

Answer:

tetrahedral aldehyde

Explanation:

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The carbonyl reforms to produce an aldehyde with the loss of the alkoxide ion.
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3 years ago

Paragraph 2 discusses two different types of thermochemical reactions. In one type of

astraxan [27]

Answer: The reaction is endothermic.

Explanation:

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3 years ago

What volume of a 0.452 m naoh solution is needed to neutralize 85.0 ml of a 0.176 m solution of h2so4?

ArbitrLikvidat [17]

H2SO4 + 2 NaOH ----> Na2SO4 + 2 H2O.

0.085 L * 0.176 mol/L = 0.01496 mol H2SO4

is neutralised by 0.01496 mol * 2

= 0.02992 mol NaOH.

1000 mL of 0.492 M NaOH

contains 0.492 moles NaPH.

0.02992 / 0.452 * 1000 mL

= 66.19 = 66 mL

6 0

3 years ago

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