3 years ago

In the middle of the page, draw a rectangle 3 inches long and oriented vertically. Both shorter sides should be an inch.

Mathematics

1 answer:

Hoochie [10]3 years ago

3 0

It is a traffic light: a vertical rectangle, divided in thre squares, each with a circle in the center.

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What is the distance from (3 1/2, 5) to (3 1/2, –12)?

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0, 17

3 1/2, 5

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3 years ago

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If r=10 and s=31 find R. Round to the nearest tenth

Vsevolod [243]

Answer: option c.

Step-by-step explanation:

You need to remember the identity:

$tan\alpha=\frac{opposite}{adjacent}$

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "R":

$\alpha =arctan(\frac{opposite}{adjacent})$

You know that you need to find the measure of "R" and $r=10$ (which is the opposite side) and $s=31$ (which is the adjacent side), you can sustitute values into $\alpha =arctan(\frac{opposite}{adjacent})$

Then, you get:

$R=arctan(\frac{10}{31})\\\\R=17.9\°$

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4 years ago

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Determine the equation of a circle with center at (8, 10) and radius 6.

andreev551 [17]

Answer:

Step-by-step explanation:

general equation for a circle at the origin is

x² + y² = r²

if the circle center is (x₀, y₀), the formula is

(x - x₀)² + (y - y₀)² = r²

(x - 8)² + (y - 10)² = 36

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3 years ago

A ball is launched into the air from a height of 12 feet at time t = 0. The function that models this situation is h(t) = -2t2 +

marshall27 [118]

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Step-by-step explanation:

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4 years ago

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The area of a rectangular plank is 4500 cm². The plank was broken into two pieces, one of which is a square and the other a rect

svp [43]

Answer:

$Xs=30cm$ and $As=900 cm^{2}$

Step-by-step explanation:

At=As+Ar; A=b.h and $At=4500 cm^{2}$ , then: At=(x+120)x so

(x+120)x=4500, $x^{2} +120x-4500=0$ Applying cuadratic equation formula: $\frac{120+-\sqrt{120^{2} -4.1.-4500} }{2} =-\frac{120+-\sqrt{14400+18000} }{2}= x1=30 and x2=-150, finally Xs=30cm, and As=900cm^{2}$

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3 years ago

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