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professor190 [17]
3 years ago
11

A sign says that the price on all music equipment is 30% off the original price. you buy an electric guitar for the sale price o

f $315.
A-what is the original price?
B-How much money did you save off of the original price?
C-What percent of the original price is the sale price?
Mathematics
2 answers:
Kitty [74]3 years ago
8 0

Answer:

a. So the electric guitar is sold for a sale price of $315 after the discount. The discount was 30%. Even though we get that amount off, we still pay 70% of the original price, because 100% (original price) - 30% is 70%.

b. An equation that can help us find the regular price of the item is through writing and solving a proportion. Set it up like this:

315/x = 70/100

This is because 315 is part of the whole and is 70% of the value of x.

Step-by-step explanation:

Okay. Let's solve this by cross multiplying the values. 315 * 100 is 31,500. 70 * x is 70x. That simplifies to 31,500 = 70x. Didivde each side by 70 to isolate the x. 70x/70 cancels out. 31,500/70 is 450. Let's check this by multiply the number by 70% and see what happens. 450 * 70% (0.7) is 315. There. x = 450. The regular price was $450.

trapecia [35]3 years ago
4 0

Answer:

a. $450

b. $135

c. 70%

Step-by-step:

\frac{70}{100}  = \frac{315}{450}  since these two fractions are equal to each other that means the orginal price is $450.

(sale price/original price)x100= % of original price

(315/450)x100=0.7=70%

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3 years ago
Soup ordinarily priced at 2 cans for .33 cents may be purchased in lots of one dozen for 1.74, what is the savings per a can whe
Sidana [21]

Answer:

Savings per can would be 0.02 cents when purchased in lots.

Step-by-step explanation:

Given:

Ordinary price of soup 2 cans = 0.33 cents.

When purchases in lots 12 cans = 1.74

We need to find the saving per can when purchased in Lots.

Solution:

Ordinary price of soup 2 cans = 0.33 cents.

1 can  = Cost of 1 can when purchased ordinary.

By Using Unitary method we get;

Cost of 1 can when purchased ordinary = \frac{0.33}{2} = 0.165\ cents/can

Now we will find the Cost of 1 can when purchased in lot.

12 cans = 1.74

1 can = Cost of 1 can when purchase in lot.

Again by using Unitary method we get;

Cost of 1 can when purchase in lot = \frac{1.74}{12} = 0.145\ cents/can

Savings = Cost of 1 can when purchase in lot - Cost of 1 can when purchased ordinary

Savings = 0.165-0.145=0.02\ cents/can

Hence Savings per can would be 0.02 cents when purchased in lots.

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3 years ago
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3 years ago
9 of 10
Aleks04 [339]

\frac{3}{10}

Answer:

^^

Step-by-step explanation:

I just pressed 27/90 on the calculator hahahha

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