(f+g)(x)=0
f (x) + g (x)=0
now,
substitute their values
x^2 -4x + x -18 = 0
x^2 -3x -18 =0
x^2 - 6x + 3x - 18 =0
x (x-6) + 3 (x-6) = 0
(x-6)(x+3) = 0
we have to find it's zeroes (or roots) now:
x-6 =0
x = 6
x +3 =0
x = -3
Answer:
hope this helps you!!!
Step-by-step explanation:
MARK AS BRAINLIEST!!
Can you do prime factoriztion
1000
100 * 10
10 * 10 * 10
27
9 * 3
3 * 3 * 3
cube root (1000/27) = 10/3
Answer:
0.3082
Step-by-step explanation: