Answer:
y=27 and x=9
Step-by-step explanation:
the ratio is 4 to 3
Answer:
-1 1/4 is greater than -1 3/4
Step-by-step explanation:
Positive and negative numbers are different. the bigger the positive number, the greater it is. The smaller the negative number, the greater it is.
yep I get the same thing what the other person is right
Hey there!
Three points to keep in mind!
- The given options are in standard form: ax+by=c
- The line is a solid line, hence, the possible outcomes would be ≤ or ≥
- The shaded part is above the line, hence, the symbol would be ≥
First, let's find the slope:
Slope : (y2-y1)/(x2-x1)
Slope : (0-3)/(2-0)
Slope : -3/2
Looking at line, we know that the y-intercept is 3 b=3
Slope intercept form:
<em>y≥(-3/2)x+3 </em>
Let's now convert this into a standard form:
<em>(3/2)x+y≥3 </em>
<em>Multiplying all the sides with 2: </em>
<em>Remember that the coefficient of 'x' shall not be negative or a fraction!</em>
<em>3x+2y≥6 </em><em>is the final answer!</em>
a) The time taken by the rocket to reach the maximum height is 2.75 seconds.
b) The maximum height of the rocket will be 127 feet.
<h3>What is speed?</h3>
Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance.
Given that:-
- A toy rocket is shot vertically into the air from a launching pad 6 feet above the ground with an initial velocity of 88 feet per second.
- The height h, in feet, of the rocket above the ground at t seconds after launch is given by the function h(t)=−16t²+88t+6.
a) The time taken by the rocket will be calculated as:-
We have a function h(t)=−16t²+88t+6. Now by taking the derivative of the function with respect to time and equating it to zero we will get the maximum time in which the rocket will reach the maximum height.
h(t) = -16t² + 88t + 6
h'(t) = 0
-32t + 88 = 0
32t = 88
t = 88 / 32 = 2.75 seconds
So the maximum time is 2.75 seconds.
b) Maximum height will be calculated as:-
Put the value of maximum time in the function h(t) = -16t² + 88t + 6 we will get the maximum height.
h(t) = -16t² + 88t + 6
h(2.75) = -16(2.75)² + ( 88 x 2.75 ) + 6
h(2.75) = 127 feet
Therefore the time taken by the rocket to reach the maximum height is 2.75 seconds and the maximum height of the rocket will be 127 feet.
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