Temperature, gravity, atmosphere and water
Multiply the two. The units will cancel out. 22 miles per gallon can be expressed as 22 miles / 1 gallon, so you can write the following:
18 gallons * 22 miles / 1 gallon
Which simplifies to 18 * 22 miles = 396 miles.
Answer:
The angular acceleration required is 0.1765 rad/ 
Explanation:
The radius of the bicycle wheel has a radius of 0.42 m.
The acceleration is for time, t = 6.8 seconds.
Initial angular velocity is given as
= 5.5 rad/s
Final angular velocity is given as
= 6.7 rad/s
Therefore from the formula for angular speed we get
=
+ (
t), where t is the time in seconds.
Therefore we get
6.7 = 5.5 + (6.8 ×
)
Therefore we get the angular acceleration,
= 
The angular acceleration required is 0.1765 rad/ 
Answer:
The intensity of light from the 1mm from the central maximu is 
Explanation:
From the question we are told that
The wavelength is 
The width of the slit is
The distance from the screen is 
The intensity at the central maximum is 
The distance from the central maximum is 
Let z be the the distance of a point with intensity I from central maximum
Then we can represent this intensity as
Now the relationship between D and z can be represented using the SOHCAHTOA rule i.e

if the angle between the the light at z and the central maximum is small
Then 
Which implies that

substituting this into the equation for the intensity
![I = I_o [\frac{sin [\frac{\pi w}{\lambda} \cdot \frac{z}{D} ]}{\frac{\pi w z}{\lambda D\frac{x}{y} } } ]](https://tex.z-dn.net/?f=I%20%3D%20I_o%20%5B%5Cfrac%7Bsin%20%5B%5Cfrac%7B%5Cpi%20w%7D%7B%5Clambda%7D%20%5Ccdot%20%5Cfrac%7Bz%7D%7BD%7D%20%20%5D%7D%7B%5Cfrac%7B%5Cpi%20w%20z%7D%7B%5Clambda%20D%5Cfrac%7Bx%7D%7By%7D%20%7D%20%7D%20%5D)
given that 
We have that
![I = I_o [\frac{sin[\frac{3.142 * 0.45*10^{-3}}{(620 *10^{-9})} \cdot \frac{1*10^{-3}}{3} ]}{\frac{3.142 * 0.45*10^{-3}*1*10^{-3} }{620*10^{-9} *3} } ]^2](https://tex.z-dn.net/?f=I%20%3D%20I_o%20%5B%5Cfrac%7Bsin%5B%5Cfrac%7B3.142%20%2A%200.45%2A10%5E%7B-3%7D%7D%7B%28620%20%2A10%5E%7B-9%7D%29%7D%20%5Ccdot%20%5Cfrac%7B1%2A10%5E%7B-3%7D%7D%7B3%7D%20%5D%7D%7B%5Cfrac%7B3.142%20%2A%200.45%2A10%5E%7B-3%7D%2A1%2A10%5E%7B-3%7D%20%7D%7B620%2A10%5E%7B-9%7D%20%2A3%7D%20%7D%20%5D%5E2)
![=I_o [\frac{sin(0.760)}{0.760}] ^2](https://tex.z-dn.net/?f=%3DI_o%20%5B%5Cfrac%7Bsin%280.760%29%7D%7B0.760%7D%5D%20%5E2)

the force of gravity on planet a is g = 5.72 m/s2
There is an object that weighs 12 kg. The object's weight on Planet A is 69 N. The equation F=mg, where F is the weight, m is the mass, and g is the force of gravity, can be used to calculate the force of gravity on Planet A:
g = F/m
g = 69 N/ 12 kg
g = 5.72 m/s2
<h3>What is the gravity force?</h3>
The force of attraction between any two objects in the universe is known as gravity or gravitational force. The mass of the object and the square of the distance between them determine the force of attraction. The weakest known force in nature, it is by far.
learn more about object has a mass here
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