Question

n electromagnetic wave in vacuum has an electric field amplitude of 611 V/m. Calculate the amplitude of the corresponding magnetic field.

Answer 1

Answer:

The  corresponding  magnetic field is  

Explanation:

From the question we are told that

    The electric field amplitude is  $E_o = 611\ V/m$

   

Generally the  magnetic  field amplitude is  mathematically represented as

              $B_o = \frac{E_o }{c }$

Where c is the speed of light with a constant value

         $c = 3.0 *0^{8} \ m/s$

So  

        $B_o = \frac{611 }{3.0*10^{8}}$

         $B_o = 2.0 4 *10^{-6} \ Vm^{-2} s$

Since 1  T  is  equivalent to  $V m^{-2} \cdot s$

         $B_o = 2.0 4 *10^{-6} \ T$