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2 years ago

13

If a plane can travel 450 miles per hour with the wind and 410 miles per hour against the wind, find the speed of the plane with

out a wind and speed of the wind. I need help with this one :(

2 answers:

Vaselesa [24]2 years ago

5 0

the plane is 430 and the wind it 20miles

Citrus2011 [14]2 years ago

3 0

The wind speed is 20
the plane is 430mph in still air

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D) decreasing the temperature lowers the average kinetic energy of the reactants.

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3 years ago

Jonathan must lift a 3000n rock using a lever. jonathan uses 300n of force to push down on the lever to move the rock. what is t

-Dominant- [34]

The load is the weight of the rock that Jonathan lifts:
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The effort instead is the force applied in input to the lever in order to lift the rock:
$E=300 N$

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2 years ago

Do solar panels create enough energy to power the car throughout the day?

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Answer:

Yes, but only if it's sunny.

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2 years ago

Bob is pushing a box across the floor at a constant speed of 1.7 m/s, applying a horizontal force whose magnitude is 70 N. Alice

OlgaM077 [116]

Answer:

a) 70 N, b) b. Each initially applied a force bigger than static friction to get the box moving and accelerating, then when the desired final speed was achieved they reduced the force to make the net force zero.

Explanation:

a) A constant speed means that magnitude of friction force is equal to the magnitude of the external force. The friction force is directly proportional to the normal force, which is equal to the weight of the box. Therefore, the magnitude of the force is 70 N.

b) Alice used initially a greater force to accelerate the box up to needed speed and later reduced the external force to keep speed constant. The right choice is option b.

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2 years ago

You are given a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4

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Answer:

The samples specific heat is 14.8 J/kg.K

Explanation:

Given that,

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Using formula of specific heat

$Q=mc\Delta T$

$c=\dfrac{Q}{m\Delta T}$

Where, m = mass

c = specific heat

$\Delta T$ = temperature

Q = heat

Put the value into the formula

$c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}$

$c=14.8\ J/kg. K$

Hence, The samples specific heat is 14.8 J/kg.K

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3 years ago