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Maru [420]
3 years ago
12

Which sizes influence the adhesive and rolling friction?

Physics
1 answer:
julsineya [31]3 years ago
4 0

juju on that beat

Explanation:

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22. A 2.0 kg ball, traveling at 1.0 m/s, rolls off of a cliff of height 3.0 m. If the
RoseWind [281]

GOOD MORNING HAVE A NICE DAY

3 0
3 years ago
Stars originate as large bodies of slowly rotating gas.Because of gravity, these clumps of gas slowly decrease in size.The angul
Tamiku [17]

Answer:

E.) conservation of angular momentum

Explanation:

The angular momentum is defined as:

L=r x mv

where r is the radius of the star, m is the mass and v the angular velocity.

and angular momentum is an amount that is conserved, so the angular momentum before the star is compressed must be equal to the angular momentum after the star was compressed:

r_{1} x mv_{1}=r_{2} x mv_{2}

the second radius is smaller than the first radius, since the star shrinked, the second angular velocity must be greater that the first.

In other words, the angular velicity increases as the star shrinks because of the conservation of angular momentum.

4 0
3 years ago
Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of
Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

A=2\times10^{-6}m^2

* The young modulus of the steel is,

Y=2.1\times10^{11}\text{ Pa}

Solution:

The young modulus of the steel in terms of the force and extension is,

Y=\frac{F\times l}{A\times dl}

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

7 0
1 year ago
What is the kinetic energy of an object with a mass of 10 kilograms traveling at a speed of 10 meters per second?
bagirrra123 [75]

Answer:

500 J

Explanation:

Kinetic Energy = (mass x velocity x velocity) ÷ 2

We know that mass = 10 kg and velocity = 10 m/s.

KE = (m × v × v) ÷ 2

KE = (10 kg × 10 m/s × 10 m/s) ÷ 2

KE = 500 J

The kinetic energy of the object is 500 J (joules). Hope this helps, thank you !!

5 0
3 years ago
PLEASE HELP ASAP 98 POINTS!!!!!!! ALL I NEED YOU GUYS TO DO IS WRITE A ONE PARAGRAPH REFLECTION ON ECLIPSES AND WRITE IT AS IF Y
makvit [3.9K]

A eclipse starts when one object in space is blocking an observer. Most commonly known as the moon blocking the sun. For us having a visual on eclipses we normally have two eclipses. We have the solar eclipse and the lunar eclipse. These are both very important on the timing and the cycles of the moon. A solar eclipse happens when the moon moves in front of the sun. This will cause a shadow to fall on only a few certain places on earth. Then a lunar eclipse is when the Sun, moon, and earth are perfectly aligned. With the earth being the middle the Sun casts its rays and causes a huge shadow on the moon.

Hope this helped!

6 0
3 years ago
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