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Liula [17]
3 years ago
15

An inductor, battery, resistance, and ammeter and switch are connected in series. If the switch, initially open, is now closed,

what is the current's final value
Physics
1 answer:
Tanzania [10]3 years ago
7 0

The question is incomplete. Here is the complete question.

An inductor, battery, resistance and ammeter and switch are connected in series. If the switch, initially open, is now closed, what is the current's final value?

a. zero

b. Battery voltage divided by inductance

c. battery voltage times inductance

d. battery voltage divided by resistance

Answer: d. battery voltage divided by resistance

Explanation: Resistance, voltage and current are related by <u>Ohm's</u> <u>Law,</u> which is explained as the current that passes through a conductor is directly proportional to the applied voltage. The constant of proportionality between them is <u>Resistance.</u>

Ohm's Law is represented by V=R.I

<u>Inductor</u> is a component that stores magnetic energy when electricity is applied to it.

<u>Ammeter</u> is an object constructed to measure electric current of a circuit and it is always connected in serie.

So, in the circuit, when the switch is closed, the "only way" for current to pass through is because of Ohm's Law, which means its magnitude will be:

I=\frac{V}{R}

Then, the correct alternative is d. voltage divided by resistance.

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R_p = \frac{d_p}{s_p} = \frac{0.005}{0.71} \approx 0.007

R_d = \frac{d_d}{s_d} = \frac{0.018}{0.71} \approx 0.0253

Since the ratio of the dime is larger than the ratio of the moon, and the ratio of the pea is smaller than the ratio of the moon, only the (a) dime can cover your view of the moon.

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