An inductor, battery, resistance, and ammeter and switch are connected in series. If the switch, initially open, is now closed,
1 answer:
The question is incomplete. Here is the complete question.
An inductor, battery, resistance and ammeter and switch are connected in series. If the switch, initially open, is now closed, what is the current's final value?
a. zero
b. Battery voltage divided by inductance
c. battery voltage times inductance
d. battery voltage divided by resistance
Answer: d. battery voltage divided by resistance
Explanation: Resistance, voltage and current are related by <u>Ohm's</u> <u>Law,</u> which is explained as the current that passes through a conductor is directly proportional to the applied voltage. The constant of proportionality between them is <u>Resistance.</u>
Ohm's Law is represented by
<u>Inductor</u> is a component that stores magnetic energy when electricity is applied to it.
<u>Ammeter</u> is an object constructed to measure electric current of a circuit and it is always connected in serie.
So, in the circuit, when the switch is closed, the "only way" for current to pass through is because of Ohm's Law, which means its magnitude will be:
Then, the correct alternative is d. voltage divided by resistance.
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Answer:
λ = 1360 m
Explanation:
Given data:
frequency of driving nails is given as 1 stroke per second mean at every 0.25 sec she hit the nails
speed of sound is given as 340 m/s
we know that the wave equation is given as
Speed = frequency × wavelength,
v = f × λ
where,
v = speed in meters/second (m/s)
f = frequency in Hertz (Hz)
substituing value to get wavelength of her driving nails
λ = 1360 m
We can calculate the density of the balloon as follows:
Therefore, the balloon will fall
Since the density of air is about 0.00123 g/cm^3 , the balloon is much more dense than the surrounding air. As a result, the balloon weighs more than the air that it displaces so the balloon will fall.