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lozanna [386]
3 years ago
12

What are the real and imaginary parts of z ? z = 32 + 41.9i

Mathematics
1 answer:
goblinko [34]3 years ago
5 0

Answer:

The real part is 32, while the imaginary part is 41.9

Step-by-step explanation:

z is a complex number. A complex number is made up of real and imaginary parts.

The real part is the number that stands alone, while the imaginary part is the number that is directly beside the i.

i is actually equal to \sqrt{-1}. There is no solution for that.

Therefore, for the given expression, the real part is 32, while the imaginary part is 41.9.

Note: the imaginary part does not contain i.

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Represent the geometric series using the explicit formula.
Dennis_Churaev [7]

The correct answer is:

b.) f(n) = 3 • (-2)^(n-1)

Further explanation:

Given sequence is:

3, -6, 12, -24, ...

We have to find the common ratio first.

Common ratio is the ratio between two consecutive terms of a geometric sequence.

It is denoted by r.

So,

Here,\\a_1=3\\a_2=-6\\a_3=12\\a_4=-24\\r=\frac{a_2}{a_1}=\frac{-6}{3}=-2\\\frac{a_3}{a_2}=\frac{12}{-6}=-2

General formula for geometric sequence is:

a_n=a_1r^{n-1}\\Here\\a_n\ is\ the\ nth\ term\\a_1\ is\ the\ first\ term\\and\\r\ is\ common\ ratio

Putting the values of a1 and r

a_n=3.(-2)^{n-1}\\f(n)=3.(-2)^{n-1}

Hence,

The correct answer is:

b.) f(n) = 3 • (-2)^(n-1)

Keywords: Geometric Sequence, Explicit formula

Learn more about geometric sequence at:

  • brainly.com/question/2048256
  • brainly.com/question/2115122

#LearnwithBrainly

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Vikentia [17]
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WINSTONCH [101]

A. The amount (A) at the end of t years of continuous compounding of principal P at rate r will be

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B. The formula for daily compounding is

... A = P(1 + r/365)^(365t)

Using the same values of P, r, t, the amount is

... A = $1000(1 +.02/365)^365 = $1020.20078

Continuous compounding produces a larger result.

The result gets larger the more often compounding occurs. Continuous compounding is the highest possible rate at which compounding can take place, so produces the largest possible result.

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... A = P(1 + r/n)^n

Each year interest is compounded this way, the amount is multiplied by

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In more compact notation, this multiplier is

... (1 +r/n)^n

When that multiplier is applied to principal P, the account balance A at the end of the year is ...

... A = P(1 +r/n)^n

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