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IRINA_888 [86]
3 years ago
5

Write an expression to represent: Four less than the quotient of a number x and 5.

Mathematics
2 answers:
antoniya [11.8K]3 years ago
5 0

Answer:

\frac{x}{5} - 4

Step-by-step explanation:

You are dividing x by 5 and then subtracting 4.

Mazyrski [523]3 years ago
4 0

Answer:

x/5 - 4

Step-by-step explanation:

The quotient of a number x and 5 refers to division of both terms.

x/5

Four less than the quotient refers to subtraction.

x/5 - 4

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Answer:

the second one

Step-by-step explanation:

when you multiply 2 negative numbers they turn into a positive

15/-5=-3

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Which three types of transformations result in congruent shapes?
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3 years ago
The coordinate plane below represents a city. Points A through F are schools in the city. graph of coordinate plane. Point A is
Firlakuza [10]
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.



Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

Substituting C(2, 2) into the system we have:
2 > 0
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as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.


Part C:
Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true

For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true

For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
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g(x)=|x|

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