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3 years ago

-9.240 ÷ -0.3

Mathematics

1 answer:

Korvikt [17]3 years ago

5 0

Answer:

30.8

Step-by-step explanation:

-9.240/-3 = 30.8 by simplifying...

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14>-2(2z+3)<br>please help me!!

Veseljchak [2.6K]

Answer:

14 > -2 (2z + 3)

First you need to distribute the -2 inside the parentheses.

14 > -2(2z) + -2(3)

14 > -4z - 6 -Add 6 to both sides of the equation

14 + 6 > -4z - 6 + 6

20 > -4z -Now divide by -4 on both sides

20 / -4 > -4z / -4

-5 > z

However, when you divide by a negative number, you MUST flip the sign.

So, the answer is:

-5 < z

Hope this helps!

6 0

3 years ago

3(x - 4)^2 = 15 using the square root method.<br><br> Please and thank you.

kherson [118]

Answer:

x = √5 + 4 , -√5 + 4

Step-by-step explanation:

3(x - 4)^2 = 15

/3 /3 (divide both sides by 3)

----------------------

(x - 4)^2 = 5

(x−4)^2⋅1/2 = ±√5 (take square root of both sides)

x - 4 = ±√5 (add 4 on both sides)

+ +4

-----------------

x = √5 + 4 , x = -√5 + 4

4 0

3 years ago

Read 2 more answers

The sum of the first n odd numbers is n^2. What is the sum of the odd numbers from 1 through 31?

jok3333 [9.3K]

Answer:

256

Step-by-step explanation:

sum of the first n odd number is n^2

if we want to find the sum of of 1 thru 31

to find out how many numbers that is

(1+31)/2 = 32/2 =16

there are 16 numbers

n^2 =16^2 =256

6 0

3 years ago

Find the perimeter of the image below:

Svetllana [295]

The perimeter should be 144.7 units

8 0

4 years ago

A sample of 64 was taken from a population, with the mean of the sample being 119 and the standard deviation of the sample being

Fofino [41]

We have the sample size, sample mean and the sample standard deviation. Since the population standard deviation is not know, we will use t-distribution to find the confidence interval.

The critical t value for 95% confidence interval and 63 degrees of freedom is 1.998.

The 95% confidence for the population mean will be:

$(119-1.998 *\frac{16}{ \sqrt{64} } ,119+1.998 *\frac{16}{ \sqrt{64} }) \\ \\ 
=(115.004, 122.996) \\ \\=(115,123)$

Thus, the 95% confidence interval for the population mean will be (115,123)

So, option A is the correct answer

6 0

3 years ago