Interesting problem ...
The key is to realize that the wires have some distance to the ground, that does not change.
The pole does change. But the vertical height of the pole plus the distance from the pole to the wires is the distance ground to the wires all the time. In other words, for any angle one has:
D = L * sin(alpha) + d, where D is the distance wires-ground, L is the length of the pole, alpha is the angle, and 'd' is the distance from the top of the (inclined) pole to the wires:
L*sin(40) + 8 = L*sin(60) + 2, so one can get the length of the pole:
L = (8-2)/(sin(60) - sin(40)) = 6/0.2232 = 26.88 ft (be careful to have the calculator in degrees not rad)
So the pole is 26.88 ft long!
If the wires are higher than 26.88 ft, no problem. if they are below, the concerns are justified and it won't pass!
Your statement does not mention the distance between the wires and the ground. Do you have it?
When t = 0, S = 2^0 = 1
<span>When t = 2, S = 2^2 = 4 </span>
<span>Change in size = 4 - 1 = 3 cubic mm. </span>
<span>Average rate of change = (S(2) - S(0))/(2-0) = (4-1)/2 = 1.5 cubic mm/month </span>
If this is your equation:
Solution:
LCD for 5 and 5x is 5x
←cross product
20x + 30 = 5x² + 25x ←simplify with distributive property
0 = 5x² + 5x - 30 ←use inverse operations to collect all terms on one side
0 = x² + x - 6 ←if possible divide by numerical GCF (This case 5)
0 = (x + 3)(x - 2) ←Factor
x = -3 or x = 2
Please check by substitution in original equation... Both work
(0, 36) would be the point on the y axis, so 36 is the y-intercept, or the b value in the equation, y = mx + b.
(12,0) is the x-intercept, so we know the line has a negative slope.
The equation for these points would be:
y = -3x + 36
LETTER B
Answer:
Years 3-4 and the percentage change was by 8%. Please vote Brainliest!
Step-by-step explanation:
