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joja [24]
4 years ago
5

A cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift. What is

the approximate volume of the tube? Round to the nearest whole cubic centimeter.
1,005 cm3
1,340 cm3
3,351 cm3
4,021 cm3
Mathematics
2 answers:
Usimov [2.4K]4 years ago
8 0
The volume of a cylinder can be calculated by multiplying the area of its base times the height. It is calculated as follows:

V = πr²h
V = π(8/2)²(20)
V = 1005.31 cm³

Therefore, the correct answer is option 1. Hope this answers the question. Have a nice day.
vfiekz [6]4 years ago
6 0

The correct answer is:

A. 1,005 cm^{3}

The approximate volume of the tube is 1,005.

|Huntrw6|

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3 years ago
-6(w+2)=w-9+3(3w+1)<br>solve for w.​
r-ruslan [8.4K]

Answer:

w = -3/8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

-6(w + 2) = w - 9 + 3(3w + 1)

<u>Step 2: Solve for </u><em><u>w</u></em>

  1. Distribute:                         -6w - 12 = w - 9 + 9w + 3
  2. Combine like terms:         -6w - 12 = 10w - 6
  3. Add 6w to both sides:     -12 = 16w - 6
  4. Isolate <em>w</em> term:                  -6 = 16w
  5. Isolate <em>w</em>:                           -3/8 = w
  6. Rewrite:                             w = -3/8
7 0
3 years ago
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