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Kipish [7]
3 years ago
10

The equilibrium constant, Kc, for the reaction

Chemistry
1 answer:
adoni [48]3 years ago
6 0

Answer : The molar concentration of N_2O_4 is, 5.1\times 10^{-7}M

Explanation :  Given,

Equilibrium constant = 4.9\times 10^{3}

Concentration of NO_2 = 0.050 M

The balanced equilibrium reaction is,

N_2O_4(g)\rightleftharpoons 2NO_2(g)

The expression of equilibrium constant for the reaction will be:

K_c=\frac{[NO_2]^2}{[N_2O_4]}

Now put all the values in this expression, we get :

4.9\times 10^3=\frac{(0.050)^2}{[N_2O_4]}

[N_2O_4]=5.1\times 10^{-7}M

Therefore, the molar concentration of N_2O_4 is, 5.1\times 10^{-7}M

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