Question

The equilibrium constant, Kc, for the reaction

Answer 1

Answer : The molar concentration of $N_2O_4$ is, $5.1\times 10^{-7}M$

Explanation :  Given,

Equilibrium constant = $4.9\times 10^{3}$

Concentration of $NO_2$ = 0.050 M

The balanced equilibrium reaction is,

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

The expression of equilibrium constant for the reaction will be:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

Now put all the values in this expression, we get :

$4.9\times 10^3=\frac{(0.050)^2}{[N_2O_4]}$

$[N_2O_4]=5.1\times 10^{-7}M$

Therefore, the molar concentration of $N_2O_4$ is, $5.1\times 10^{-7}M$