Explanation:
( a )
The decomposition reaction of KClO₃ to form diatomic oxygen gas is the following way -
2 KClO₃ ( s ) -------> 2 KCl ( s ) + 3O₂ ( g )
( b )
The reaction of solid metal of Aluminum with Iodine in the following way -
2 Al ( s ) + 3 I₂ ( s ) ------> Al₂I₆ ( s )
( c )
The reaction of sodium chloride with aqueous sulfuric acid is as follow -
2 NaCl ( s ) + H₂SO₄ ( aq ) ------> 2 HCl ( g ) + Na₂SO₄ ( aq )
( d )
The reaction of phosphoric acid with potassium hydroxide , in the following way -
H₃PO₄ ( aq ) + KOH ( aq ) ------> KH₂PO₄ ( aq ) + H₂O ( l )
Answer:
A 100-watt light bulb takes 100 seconds to use 10,000 J of electrical energy.
Explanation:
Power refers to the amount of work done (or energy consumed) per unit of time. It is usually measured in watts (W), which is equal to 1 Joules per second (
)
So, by definition, to calculate the power consumed or supplied in a time interval the following expression is used:
where P is the power measured in Watts, W is the work measured in Joules, and t is the time measured in seconds.
In this case:
- P=100 Watt
- W= 10,000 J
- t= ?
Replacing:
Solving:
t=100 seconds
<u><em>
A 100-watt light bulb takes 100 seconds to use 10,000 J of electrical energy.</em></u>
<u><em></em></u>
Answer:
44.91% of Oxygen in Iron (III) hydroxide
Explanation:
To solve this question we must find the molar mass of Fe(OH)3 and the molar mass of the oxygen in this molecule. Percent composition will be:
<em>Molar mass Oxygen / molar mass Fe(OH)3 * 100</em>
<em />
<em>Molar mass Fe(OH)3 and oxygen:</em>
1Fe = 55.845g/mol*1 = 55.845
3O = 16.00g/mol*3 = 48.00 - Molar mass of Oxygen
3H = 1.008g/mol*3 = 3.024
55.845 + 48.00 + 3.024 =
106.869g/mol is molar mass of Fe(OH)3
% Composition of oxygen is:
48.00g/mol / 106.869g/mol * 100 =
<h3>44.91% of Oxygen in Iron (III) hydroxide</h3>
Given the model from the question,
- The products are: N₂, H₂O and H₂
- The reactants are: H₂ and NO
- The limiting reactant is H₂
- The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂
<h3>Balanced equation </h3>
From the model given, we obtained the ffolowing
- Red => Oxygen
- Blue => Nitrogen
- White => Hydrogen
Thus, we can write the balanced equation as follow:
3H₂ + 2NO —> N₂ + 2H₂O + H₂
From the balanced equation above,
- Reactants: H₂ and NO
- Product: N₂, H₂O and H₂
<h3>How to determine the limiting reactant</h3>
3H₂ + 2NO —> N₂ + 2H₂O + H₂
From the balanced equation above,
3 moles of H₂ reacted with 2 moles of NO.
Therefore,
5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO
From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of H₂.
Thus, H₂ is the limiting reactant
Learn more about stoichiometry:
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Answer:
C
Explanation:
You mix different thing together to make a new thing.
